2xy - 12xz + 3y - 18z
How would you factor this problem?
2007-01-05 19:22:17 · 8 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
First: when you have 4 terms > combine "like" terms in parenthesis >
(2xy +3y) - (12xz - 18z)
Sec: factor both sets of parenthesis >
y(2x + 3) - 6z(2x + 3)
Third: combine one inner term with the outer term >
(2x+3)(y-6z)
2007-01-06 07:36:58 · answer #1 · answered by ♪♥Annie♥♪ 6 · 0⤊ 0⤋
Start with a pair that have some common factors.
2xy - 12xz + 3y - 18z
= 2x(y - 6z) + 3y - 18z (take out a common factor of 2x)
= 2x(y - 6z) + 3(y - 6z) (take out a common factor of 3)
= (y - 6z)(2x + 3) (take out a common factor of y - 6z)
Bravo!
I am sure you can do it.
2007-01-05 19:29:43 · answer #2 · answered by SohCK 1 · 0⤊ 0⤋
factor the first two terms and the last two terms separately:
2xy - 12xz + 3y - 18z =
2x(y - 6z) + 3(y - 6z)
now the two terms have the (y - 6z) in common. factor it out:
2x(y - 6z) + 3(y - 6z) =
(2x+3)(y-6z), which is the factored equation
2007-01-05 19:28:41 · answer #3 · answered by Anonymous · 0⤊ 0⤋
This expression can be factored by grouping - you can factor 2x from the left two terms and a 3 from the right two terms
2x(y - 6z) + 3(y - 6z)
Which can be written
(y - 6z)(2x + 3)
Applying the distributive rule: a(b + c) = ab + ac from right to left
2007-01-05 19:27:40 · answer #4 · answered by Albertan 6 · 0⤊ 0⤋
2xy - 12xz + 3y - 18z
2x(y - 6z) + 3(y - 6z)
(y - 6z)(2x + 3)
2007-01-05 19:26:49 · answer #5 · answered by ? 2 · 0⤊ 0⤋
2xy - 12xz + 3y - 18z
2x(y - 6z) + 3(y - 6z
(2x + 3)(y - 6z)
- - - - - - - -s-
2007-01-05 22:21:35 · answer #6 · answered by SAMUEL D 7 · 0⤊ 0⤋
2xy - 12xz + 3y - 18z
= 2x(y - 6z) + 3y - 18z
= 2x(y - 6z) + 3(y - 6z)
= (y - 6z)(2x + 3)
= ( 2x + 3 ) ( y - 6z )
2007-01-05 19:28:36 · answer #7 · answered by The Soulforged 2 · 0⤊ 0⤋
Given exp.=2x(y-6z)+3(y-6z)
=(y-6z)(2x+3y) ans
2007-01-05 19:51:41 · answer #8 · answered by alpha 7 · 0⤊ 0⤋