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plz give link also.......

2007-01-05 18:51:20 · 13 answers · asked by chandan27_sachin 1 in Science & Mathematics Physics

13 answers

More generally, for any symmetry of a body, its center of mass will be a fixed point of that symmetry.

2007-01-05 19:11:27 · answer #1 · answered by The Last Paladin 4 · 0 0

yes the center of the mass can lie outside the body also as in case of a ring which is hollow from the middle and its center of gravity lies in the air in the middle of it.

2007-01-06 05:00:10 · answer #2 · answered by Daksh Jain 1 · 0 0

Yes, any object that curves back on itself can have its center of mass outside its body. Think of a hook or a ring.

2007-01-06 03:12:23 · answer #3 · answered by hznfrst 6 · 0 0

of course s the center of mass of the object can lie outside. for example take a returning boomberang.

2007-01-07 07:25:59 · answer #4 · answered by sona 1 · 0 0

yes
cosider a ring ,a hose shoe . even think of a stone tied to a thread and whirled arround in a circle.then the centre of mass of the system lies at the pt of rotation .

also the CM of eath moon system lies closer to earth!

2007-01-06 05:30:47 · answer #5 · answered by khandavillimahesh k 2 · 0 0

yes definately...centre of mass lies outside the body in case of a ring...etc etc..

2007-01-06 03:25:04 · answer #6 · answered by Neelu 2 · 0 0

Do you mean Centre of Gravity...???? If so... it does lie outside the body sometimes...

2007-01-06 03:11:35 · answer #7 · answered by Rrrahul 2 · 0 0

yes, think pole-vaulter... during their ascent, their centre, physically is actually UNDER the bar, while their body curves over the top. Cool stuff.

2007-01-06 02:53:59 · answer #8 · answered by Anonymous · 0 0

yes centerof mas lie outside of body in case hollow objects it llie outside of the object example in ringgs , hollow cylinder,hollow hemisphere

2007-01-06 03:57:02 · answer #9 · answered by vande_matram27011987 2 · 0 0

http://hyperphysics.phy-astr.gsu.edu/hbase/cm.html
http://en.wikipedia.org/wiki/Center_of_mass
The center of mass \mathbf{R} of a system of particles is defined as the average of their positions \mathbf{r}_i, weighted by their masses mi:

\mathbf{R} = \frac 1M \sum m_i \mathbf{r}_i

where M is the total mass of the system, equal to the sum of the particle masses.

For a continuous distribution with mass density \rho(\mathbf{r}), the sum becomes an integral:

\mathbf R =\frac 1M \int \mathbf{r} \; dm = \frac 1M \int\rho(\mathbf{r})\, \mathbf{r} \ dV =\frac{\int\rho(\mathbf{r})\, \mathbf{r} \ dV}{\int\rho(\mathbf{r})\ dV}

If an object has uniform density then its center of mass is the same as the centroid of its shape.
http://www.phys.psu.edu/~demo/Scott/energy/center_of_mass.html
http://dev.physicslab.org/Chapter.aspx?cid=22

2007-01-06 03:01:57 · answer #10 · answered by Anonymous · 0 0

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