2007-01-05 17:44:44 · 10 answers · asked by Anonymous in Entertainment & Music ➔ Celebrities
i don't think they suit at all, Vanessa is to much of a loud mouth.
I loved Jess & Nick... They were Barbie & Ken, just perfect.!
2007-01-05 17:58:04 · answer #1 · answered by Dee 5 · 0⤊ 0⤋
Nope Jessica is in Vanessa is out Why is Vanessa a superstar? All she does is host TRL on MTV. Jessica easily has expertise and has a extra effective personality then Vanessa. Nick is actual on the rebound and its sparkling he nevertheless cares about Jess. I help Jess one hundred%
2016-12-01 21:50:37 · answer #2 · answered by hertling 4 · 0⤊ 0⤋
I don't think so, to me there is something about Vanessa I don't like, don't get me wrong, I hardly like Nick either, but it was werid seeing them kiss on national television for New Years. But what are you gonna do.
2007-01-05 18:43:06 · answer #3 · answered by face_downxx 3 · 0⤊ 0⤋
No not at all i think its weird, i was such a huge fan of newlyweds and still am a huge fan of the both of them but have found that i am not sure if i like them all that much apart, nick and jessica were deff. much better together!
2007-01-05 17:47:15 · answer #4 · answered by cakelady0329 1 · 1⤊ 0⤋
Anything would beat the heck out of airhead Jessica I think.
Vanessa is pretty but if I see her wearing that fat suit one more time for a "sensational news story" I will puck!
Since Ugly Betty that seems to be all the rage.
Like who don't know ugly/fat people are the butt of all jokes?
Come on now...
2007-01-05 18:03:01 · answer #5 · answered by Cat 5 · 0⤊ 1⤋
eww no. Vanessa is way to hot for Nick.
2007-01-05 18:03:13 · answer #6 · answered by angelbabydia 2 · 0⤊ 2⤋
She aight, but I know he's missing Jessica!
Hoooty-Hoooooooooooooooooooooooo
2007-01-05 17:47:17 · answer #7 · answered by Sethco 3 · 2⤊ 1⤋
nope.
2007-01-05 17:50:39 · answer #8 · answered by scooprandell 7 · 1⤊ 0⤋
yeah sure they are
2007-01-05 17:46:09 · answer #9 · answered by Anonymous · 0⤊ 1⤋
they are garbage
2007-01-05 17:57:55 · answer #10 · answered by sammie 1 · 1⤊ 0⤋