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Question

1.A jar of tea is placed in sunlight until it reaches an equilibrium temperature of 32°C. In an attempt to cool the liquid, which has a mass of 180 g, 134 g of ice at 0°C is added. At the time at which the temperature of the tea (and melted ice) is 16°C, determine the mass of the remaining ice in the jar. Assume the specific heat capacity of the tea to be that of pure liquid water

Answer 1

Mt*Ct*dt=Mi L+Mi*ci*dt
180gm*1cal c^-1 gm^-1*(32-16)=Mi*80(latent heat of ice)+Mi*1*(16-0)
180*16*1=Mi(80+16)
2880/96=Mi
Mi=30 gm

so remaining ice=134-30=104gm