x=1
1= -1
y= -1
x = 0
2007-01-05 16:19:40 · 7 answers · asked by janie j 1 in Science & Mathematics ➔ Mathematics
You mean y = -x^2 + 1.
This is a vertical, downward opening parabola. it crosses the x-axis at x = -1 and x = 1. The (vertical) axis of symmetry is thus x = 0.
Nick's answer, aside from being wrong, isn't even one of the choices.
2007-01-05 16:22:31 · answer #1 · answered by ? 6 · 0⤊ 0⤋
The axis of symmetry for y=x^2+1 is at y=0.
2007-01-06 00:22:53 · answer #2 · answered by Nick R 4 · 0⤊ 1⤋
x = 0
2007-01-06 00:41:48 · answer #3 · answered by ebiz1@sbcglobal.net 2 · 0⤊ 0⤋
what is the axis of symmetry for the graph y= -x2 + 1??
dy/dx = -2x
Set this equal 0 getting x =0
So the vertex is at x= 0 and y=1
Since the axis of symmetry is a vertical line that passes through the vertex, its equation must be x = 0.
Just another way to do it.
2007-01-06 00:50:14 · answer #4 · answered by ironduke8159 7 · 0⤊ 0⤋
Compare y= -x^2 + 1 to the vertex form of a quadratic function
y = (x-h)^2 + k.
The axis of symmetry is x = h.
Since h = 0 for the problem, the axis of symmetry is
x = 0.
2007-01-06 00:32:14 · answer #5 · answered by sahsjing 7 · 0⤊ 0⤋
um well assuming that you really mean y = (-x)^2 +1, the axis of symmetry is x = 0. what you have there is a line, so no symmetry.
2007-01-06 00:31:03 · answer #6 · answered by Smart Blonde 2 · 1⤊ 1⤋
This is a vertical parabola . Assuming from y= (-x)^2+1 the answer is x=0.
2007-01-06 00:45:04 · answer #7 · answered by Anonymous · 0⤊ 0⤋