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eg. Solve the equation, noting any double roots: x^3+9x=6x^2

2007-01-05 12:03:21 · 4 answers · asked by z1 2 in Science & Mathematics Mathematics

4 answers

A double root is something that has a square factor, like x^2=0 which has x=0 as a "double" root.

For this equation subtract to get x^3-6x^2+9x=0 then factor out the x: x(x^2-6x+9)=0 then factor more to get x(x-3)(x-3)=0 so x=0 is one solution and x=3 is another solution and x=3 is a double root [two factors of (x-3)]

2007-01-05 12:05:53 · answer #1 · answered by a_math_guy 5 · 0 0

Double Root

2017-01-14 13:15:56 · answer #2 · answered by Anonymous · 0 0

To explain what a double root is, I'll first solve your equation.

x^3 + 9x = 6x^2

x^3 - 6x^2 + 9x = 0
x(x^2 - 6x + 9) = 0
x(x - 3)(x - 3) = 0

Therefore, x = {0, 3, 3}

The Fundamental Theorem of Algebra states that ANY polynomial equation of degree n has exactly n roots (including multiplicity). It seems a bit abnormal to say that the solutions are x = {0, 3, 3} when it makes more sense to say x = {0, 3}. The fact that there is another hidden "3" that results from the way the polynomial factors is why it is a double root; because there are 2 of them in all.

2007-01-05 12:53:33 · answer #3 · answered by Puggy 7 · 0 0

A double root Double is a root of a polynomial equation with multiplicity 2. Also refers to a zero of a polynomial function with multiplicity 2.

Guido

2007-01-05 12:10:49 · answer #4 · answered by Anonymous · 0 0

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