2007-01-05 10:32:41 · 5 answers · asked by deborah j 1 in Science & Mathematics ➔ Mathematics
You asked the same question again!
Ok, there must be a catch to this...
for general values of a, the LCM would be a(a+7)
For particular values of a, that is, if a is a multiple of 7, then you could write a = 7b
Then for the LCM of 7b, (7b+7)
the factors are 7, b, (b+1) and the LCM would be 7b(b+1)
For example, if a = 14 then a = 7b = 7x2 so b = 2
And the LCM of a and a+7, that is, 14 and 21, would be
7x2x3 = 42, which is less than 14 x 21 = 294
Since 7 is a prime number this is the only way you could break it down and come up with a LCM smaller than a(a+7) for particular values of a.
Happy now?
2007-01-05 10:49:06 · answer #1 · answered by Joni DaNerd 6 · 0⤊ 0⤋
What is the LCM of 6 and 7? Answer. 1 is their only common divisor. Therefore their LCM is 6 × 7 = 42.
2007-01-05 10:38:02 · answer #2 · answered by kitty 3 · 0⤊ 0⤋
it depends on what a is. If a is a multiple of 7, then it is a+7 (e.g, if a =7, the LCM of 7 and 14 is 14). If a is not a multiple of 7 then it is a(a+7) since 7 is prime.
2007-01-05 10:58:40 · answer #3 · answered by Walter B 2 · 0⤊ 0⤋
a(a+7)
In other words, the 2 numbers multiplied together
2007-01-05 10:35:50 · answer #4 · answered by rosie recipe 7 · 1⤊ 0⤋
Whoa, deja vu.....
2007-01-05 10:34:15 · answer #5 · answered by Anonymous · 0⤊ 0⤋