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It may seem like the black one at first, but rough absorbs more sunlight than smooth, and black more than white.

2007-01-05 10:30:12 · 5 answers · asked by hanalulu2☺♥☻ 4 in Science & Mathematics Earth Sciences & Geology

and please answer WHY?

2007-01-05 10:35:50 · update #1

Please pay attention to the fact that the white is ROUGH too and black is SMOOTH rough absorbs more sunlight than smooth

2007-01-05 10:41:47 · update #2

there is supposed to be a comma after
"SMOOTH"...

2007-01-05 10:42:34 · update #3

and if black does absorb more sunlight, does this mean that people with black hair get warmer?

2007-01-05 11:28:32 · update #4

5 answers

the white, rough surface has more surface area than the black,smooth surface which is almost has less than half of the
surface area, so that means that the white actually has more
surface reflectivity than the black. black in any form will absorb
more light than white for example, solar cells are all made with a dark color to increase the absorption of light.

2007-01-05 11:02:04 · answer #1 · answered by barrbou214 6 · 0 0

Your question is which surface absorbs more sunlight. Both black and white absorb the same amount of sunlight. However, white reflects the suns rays better than black due to absorption. Therefore, black is much hotter to the touch than white.

2007-01-05 10:37:16 · answer #2 · answered by ? 3 · 0 0

products do not 'emit warmth'. They habit warmth, and they emit basic. warmth is the kinetic skill of molecules. basic is photons. they're diverse yet appropriate ideas. There are 3 techniques to delivery warmth: conduction, convection, and radiation. Conduction takes position even as the products are in actual contact. as an celebration, your body conducts warmth to an ice dice once you %. it up. Convection takes position even as there's a transferring fluid present. warmth might want to be absorbed (performed into) the molecules of the fluid, and transported to a special area. Radiative warmth move is the third variety. this kind is the really variety to act throughout a vacuum (alongside with outer area). to comprehend how this works, evaluate that one and all products with a temperate above absolute 0 emit radiation. the better the temperature, the further radiation they emit, and the better the frequency of that radiation. it truly is why all sparkling products first glow red, then orange, then yellow, then white, then blue as they improve in temperature. So, imagine you've 2 surfaces with a vacuum in-between. in the journey that they are both ideal blackbodies with a similar temperature, they both emit a similar quantity of radiation (in step with area) and they both take in one hundred% of the radiation that strikes them (the definition of a blackbody). in the journey that they have got diverse temperatures, the speed of warm temperature move between both will be proportional to warmth move === e*(T1^4 - T2^4) the position T1 and T2 are the temperatures (in Kelvins or Rankines) of both products, and e is the emissivity coefficient of the surfaces. For a blackbody, e = a million. For actual surfaces, e is someplace between 0 and a million. If the article change right into a ideal reflect, e might want to be 0, and the article might want to take in no radiation. it would want to also emit no radiation, it truly is had to fulfill thermodynamics (in case you construct something that absorbed radiation without freeing any of its own, it would want to improve its temperature to infinity, and may want to for this reason be a loose skill gadget).

2016-12-01 21:28:07 · answer #3 · answered by ? 4 · 0 0

black

2007-01-05 10:32:15 · answer #4 · answered by TexasGirl 3 · 0 0

dark colors asorb light hence there color. white is all the colors combined so that means they're being reflected
excuse my bad grammer

2007-01-05 10:38:00 · answer #5 · answered by Brian 4 · 0 0

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