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sequences have in common is

a)115 b)187 c)258 d)445 e)1006

Please show your work.

Thanks

2007-01-05 09:54:06 · 6 answers · asked by Anonymous in Science & Mathematics Mathematics

6 answers

258

2007-01-05 09:57:38 · answer #1 · answered by raj 7 · 0 2

3,20,37,54,71

An = 3 + 17(n - 1)

115 = 3 + 17(n - 1)
112 = 17(n - 1)
n - 1 = (112/17)
n = (112/17) + 1

187 = 3 + 17(n - 1)
184 = 17(n - 1)
n - 1 = (184/17)
n = (184/17) + 1

258 = 3 + 17(n - 1)
17(n - 1) = 255
n - 1 = 15
n = 16

-----------------------------

An = 16 + 11(n - 1)

115 = 16 + 11(n - 1)
99 = 11(n - 1)
9 = n - 1
n = 10

187 = 16 + 11(n - 1)
11(n - 1) = 171
n - 1 = (171/11)
n = (171/11) + 1

258 = 16 + 11(n - 1)
242 = 11(n - 1)
n - 1 = 22
n = 23

So the 16th term of the first sequence is equal to 23rd term of the second sequence

ANS : c.) 258

2007-01-05 10:48:28 · answer #2 · answered by Sherman81 6 · 0 1

c-258. The easiest way to determine the next common term in a 2 sequence problem its pretty simple. Multiply both sequences and add the previous common term that were able to find

2007-01-05 10:41:08 · answer #3 · answered by h-townguy 3 · 0 1

c) 258

The next time occurs at 71 + 11*17 = 258

The first series is increasing by 11 and the second series in increasing by 17

In other words, you take 71 and add 17 multiples of 11 to get 258, which would be the same as taking 71 and adding 11 multiples of 17.

2007-01-05 10:00:10 · answer #4 · answered by bkc99xx 6 · 1 1

8 and 8

2016-05-23 07:01:06 · answer #5 · answered by Anonymous · 0 0

none of the above. you probably know that too.

2007-01-05 10:04:00 · answer #6 · answered by steve 4 · 0 2

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