This is the equation:
(y1 - y2) / (x1 - x2) = slope
1. Pick two points.
----Pretend that these are your points: (4,5) and (2,3).
2. Put the points in the equation (y1 must be with x1!)
----Therefore: (5 - 3) / (4 - 2)
3. Solve equation
---- (5 - 3) / (4-2) = 2/2 = 1.
So, the slope of a line with points (4,5) and (2,3) is 1.
2007-01-05 09:44:02
·
answer #1
·
answered by Anonymous
·
1⤊
0⤋
The slope is equal to the rise over the run,that means if you have a line with points (x1,y1) and (x2,y2) the slope of the line would be (y2-y1)/(x2-x1). For example:
With points (1,3) and (4,5) the slope would be (5-3)/(4-1) which equals 2/3 or .6667.
2007-01-05 17:44:39
·
answer #2
·
answered by Megan925 1
·
0⤊
0⤋
rate of change = slope =
y(2) - y(1) / x(2) - x(1)
ex: these are the values given:
X Y
(4,6)
(6,8)
(8,10)
to find the slope you would do this:
10 - 6 / 8 - 4 = 4/4 = 1
2007-01-05 17:52:55
·
answer #3
·
answered by Anonymous
·
0⤊
0⤋
You would first find two points on the line and then you would take the x-coordinates of the two points and subtract them,
and then you would take the y-coordinates and subtract them in the same order as you subracted the other points [point 1 coordinate subtracted by point 2 coordinate]
then you would take the x-coordinates difference and the y-coordinate difference and put them in a fraction. [with the x-coordinate difference on top].
Then you would reduce the fraction if necessary.
2007-01-05 17:44:12
·
answer #4
·
answered by navdeepkaur 3
·
0⤊
0⤋
Slope Formula Given Two Points:
Given two points (x1,y1) and (x2,y2)
____rise____change in Y_____y2-y1
m= -----__=_--------------__=__------
____run____change in X_____x2-x1
--=divided by
__=spaces (don't pay attention to this)
2007-01-05 18:01:35
·
answer #5
·
answered by ツ 1
·
0⤊
1⤋
you take the second y value minus the first y value and divide by the second x value minus the first x value.
two points: (x,y) and (x2,y2)
equation: (y2-y)/(x2-x)
then reduce if it can be reduced.
2007-01-05 17:45:08
·
answer #6
·
answered by Anonymous
·
0⤊
0⤋
It is really easy when you figure it http://www.learningwave.com/lwonline/algebra_section2/slope3.htmlout this will help alot.
2007-01-05 17:45:37
·
answer #7
·
answered by Tim Sing 1
·
0⤊
0⤋