(A=12 B=32.2 c=AxB) 16-A+C divided by 2xC minus 1\2 A+B x 1\3 of B divided by 3.63 less the amount of 2\3 of BxC then divided by half the amount of Bx45 subtracted from 89.9 = ?
2007-01-05 08:23:15 · 4 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
Well solved the exact way the question is written...the answer is -23,180.19267
2007-01-05 10:55:18 · answer #1 · answered by Saphira 3 · 0⤊ 0⤋
A=12
B=32.2 = 64
c=AB
16-12+AB : 2C - (1\2 A+B x 1\3 of B) : 3.63 - amount of 2\3BC : 1/2 the amount of 45B subtracted from 89.9 =
16 - 12 + 1/2 - 1338:3,63 -2/3(64².12 over -89,9 + 1360,1) =
9/2 - (44600 over 121) minus (8 x 7932 over 1360,1) =
Aff!
Now, you continue
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2007-01-05 16:31:32 · answer #2 · answered by aeiou 7 · 0⤊ 0⤋
solve for C and then work each part of the equation. You'll get it. Oh, and remember that it is 16 - A +C not A+C-16! Good luck
2007-01-05 16:47:12 · answer #3 · answered by kubi 1 · 1⤊ 0⤋
Each ambiguity in your statement of the problem doubles the number of possible solutions. As written, I make it that there are 16 possible equations that you can set up.
2007-01-05 17:05:32 · answer #4 · answered by Helmut 7 · 0⤊ 0⤋