YES OR NO!! CUZ HE IS HOTTT!!!!!!!!!!!
2007-01-05 07:55:37 · 19 answers · asked by ruphio_hook 1 in Entertainment & Music ➔ Celebrities
What does it matter? Unless you have any chance whatsoever to actually hook up with him, then his sexual preference doesn't affect you one way or another. Eye candy is eye candy, whether they're gay or straight.
2007-01-05 07:57:34 · answer #1 · answered by ckmclements 4 · 2⤊ 0⤋
He is not gay but he's bi, I'm a friend of Audrey and she tells me all kinds of stuff oh and Audrey and Brendon are still going out.
2016-05-23 06:39:02 · answer #2 · answered by Anonymous · 0⤊ 0⤋
He has not officially come out,( that dosen't mean he is a closet case, he just never said he was or wasen't) but I've never heard anyone assume he was gay... did you hear something
2007-01-05 08:00:06 · answer #3 · answered by Lauren 3 · 0⤊ 0⤋
He may be happy all the time... would it change the way you look at him if he were? I think once hot, always hot. What they do on the side is of no importance to me because I wont ever be with them...
2007-01-05 07:57:48 · answer #4 · answered by glorymomof3 6 · 1⤊ 0⤋
yes
2007-01-05 07:58:10 · answer #5 · answered by Lg 4 · 0⤊ 0⤋
Who knows? Who cares?
It is not like you are going to get together with him anyway. Just enjoy the sight :-)
2007-01-05 07:57:43 · answer #6 · answered by Great Dane 4 · 2⤊ 0⤋
nope. everyone from panic! have girlfriends but i think brendon and his girlfriend broke up. but he is so hot.
2007-01-05 10:19:50 · answer #7 · answered by Anonymous · 0⤊ 0⤋
I dont think so, but on the other hand i am not sure maybe this will change your mind.http://cdn-59.cdn.buzznet.com/assets/users11/xakeshax/default/brendon_urie--large-prf-1150255987--large-msg-115164393857.jpg
2007-01-05 07:59:30 · answer #8 · answered by IcanHelpyou:) 3 · 0⤊ 0⤋
Why does it matter? It's not like you really have a chance with him anyway.
2007-01-05 07:58:07 · answer #9 · answered by lp_fanatic_2 4 · 1⤊ 0⤋
So gay, and yes he is hott
2007-01-05 07:57:15 · answer #10 · answered by darling 2 · 1⤊ 0⤋