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To change the temprature from degrees Fahrenheit to degrees celsius, use formula:
c=5/9(F-32).

I need to find the F and C intercepts. I would like someone to show me how to do this.

Thanks a bunch :)
Cristy

2007-01-05 07:42:22 · 10 answers · asked by Anonymous in Science & Mathematics Mathematics

All the answers were great thanks :D

2007-01-07 14:22:49 · update #1

10 answers

1. Find the "C" intercept. First: replace "0" with the "F" variable >

C = 5/9(0 - 32)

Sec: multiply the numerators >

C = (5/9)(-32)
C = -160/9

2. Find the "F" intercept. First: replace "0" with the "C" variable >

0 = 5/9(F - 32)

Sec: use distribution > multiply 5/9 with both terms in the parenthesis >

0 = (5/9)F - (5/9)(32)
0 = (5/9)F - 160/9

Third: eliminate fractions > multiply the denominator by everything and cancel "like" terms >

9(0) = (9)(5/9)F - 9(160/9)
0 = 5F - 160

*Add 160 to both sides >

0 + 160 = 5F - 160 + 160
160 = 5F

*Solve for "F" by isolating it > divide both sides by 5 >

160/5 = 5F/5
32 = F
F = 32

2007-01-05 09:22:45 · answer #1 · answered by ♪♥Annie♥♪ 6 · 0 0

The F and C intercepts are just like the x and y intercepts.

The C-intercept is the value of C where F = 0:

C = 5/9(0 - 32) = -160/9 = -17 7/9 degrees Celsius.

The F-intercept is the value of F where C = 0:

0 = 5/9(F - 32)

Multiply both sides by 9/5:

0 = F - 32
F = 32 degrees Fahrenheit (of course!)

2007-01-05 07:56:35 · answer #2 · answered by Jim Burnell 6 · 1 0

c=5/9(f-32)
to find the f intercept, set c=0
0=5/9 (f-32) divide by 5/9
0=f-32 add 32 to each side
f=32

to find the c intercept set f=0
c=5/9(0-32)=-5*32/9=-160/9=-17.77....

2007-01-05 07:58:07 · answer #3 · answered by yupchagee 7 · 1 0

C. & B. contained in the point (0, 6), 6 is the y-intercept, and in slope-intercept form y=mx+b, b equals the y-intercept, for this reason b is replaced with 6 and the you get C. also in B 12 even as divided by 2 equals 6, for this reason it truly is likewise perfect

2016-12-01 21:17:18 · answer #4 · answered by Anonymous · 0 0

to find the intercepts you just set the other variable to zero

i.e. to find the F intercept, set c=0 then solve for F

0=5/9(F-32) --> 9/5=(F-32) -----> F=(9/5)+32 --->
F=169/5 or about 33.8

just do the same for c

2007-01-05 07:54:31 · answer #5 · answered by rabies1979 3 · 0 1

for F intercept putC=0
0=(5/9)(F-32)
multiplying by (9/5)
0=F-32
adding 32
F=32

for C intercept put F=0
C=(5/9)(-32)
C=-160/9

2007-01-05 08:02:51 · answer #6 · answered by raj 7 · 1 0

When F=0, C = (5/9)(-32) = -17 7/9

When C = 0,
0 = (5/9)(F-32)
0 = F - 32
32 = F ....... by definition, in F system water freezes at 32, in C system, at 0.

2007-01-05 09:11:43 · answer #7 · answered by Philo 7 · 1 0

I think you want to find the temperature at which F is equal to C so just set C = F and solve the equation F = 5/9(F -32) this will give the temperature at which they are equal. I will give you a hint. It is very cold.

2007-01-05 07:52:36 · answer #8 · answered by rscanner 6 · 0 0

At c = 0, you get F-intercept = 32.
At F = 0, you get c-intercept = -160/9

F = 9c/5 + 32

2007-01-05 07:55:51 · answer #9 · answered by sahsjing 7 · 0 1

c=5/9(f-32) *9
9c=5(f-32)
9c=5f-160 by arrange the equation
5f-9c=160 /160
f/32+c/(-160/9)=1
then f_intercept is 32 &c_intercept is -160/9

2007-01-05 08:13:41 · answer #10 · answered by eissa 3 · 1 0

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