1. Find the "C" intercept. First: replace "0" with the "F" variable >
C = 5/9(0 - 32)
Sec: multiply the numerators >
C = (5/9)(-32)
C = -160/9
2. Find the "F" intercept. First: replace "0" with the "C" variable >
0 = 5/9(F - 32)
Sec: use distribution > multiply 5/9 with both terms in the parenthesis >
0 = (5/9)F - (5/9)(32)
0 = (5/9)F - 160/9
Third: eliminate fractions > multiply the denominator by everything and cancel "like" terms >
9(0) = (9)(5/9)F - 9(160/9)
0 = 5F - 160
*Add 160 to both sides >
0 + 160 = 5F - 160 + 160
160 = 5F
*Solve for "F" by isolating it > divide both sides by 5 >
160/5 = 5F/5
32 = F
F = 32
2007-01-05 09:22:45
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answer #1
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answered by ♪♥Annie♥♪ 6
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The F and C intercepts are just like the x and y intercepts.
The C-intercept is the value of C where F = 0:
C = 5/9(0 - 32) = -160/9 = -17 7/9 degrees Celsius.
The F-intercept is the value of F where C = 0:
0 = 5/9(F - 32)
Multiply both sides by 9/5:
0 = F - 32
F = 32 degrees Fahrenheit (of course!)
2007-01-05 07:56:35
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answer #2
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answered by Jim Burnell 6
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c=5/9(f-32)
to find the f intercept, set c=0
0=5/9 (f-32) divide by 5/9
0=f-32 add 32 to each side
f=32
to find the c intercept set f=0
c=5/9(0-32)=-5*32/9=-160/9=-17.77....
2007-01-05 07:58:07
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answer #3
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answered by yupchagee 7
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C. & B. contained in the point (0, 6), 6 is the y-intercept, and in slope-intercept form y=mx+b, b equals the y-intercept, for this reason b is replaced with 6 and the you get C. also in B 12 even as divided by 2 equals 6, for this reason it truly is likewise perfect
2016-12-01 21:17:18
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answer #4
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answered by Anonymous
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to find the intercepts you just set the other variable to zero
i.e. to find the F intercept, set c=0 then solve for F
0=5/9(F-32) --> 9/5=(F-32) -----> F=(9/5)+32 --->
F=169/5 or about 33.8
just do the same for c
2007-01-05 07:54:31
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answer #5
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answered by rabies1979 3
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for F intercept putC=0
0=(5/9)(F-32)
multiplying by (9/5)
0=F-32
adding 32
F=32
for C intercept put F=0
C=(5/9)(-32)
C=-160/9
2007-01-05 08:02:51
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answer #6
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answered by raj 7
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When F=0, C = (5/9)(-32) = -17 7/9
When C = 0,
0 = (5/9)(F-32)
0 = F - 32
32 = F ....... by definition, in F system water freezes at 32, in C system, at 0.
2007-01-05 09:11:43
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answer #7
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answered by Philo 7
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I think you want to find the temperature at which F is equal to C so just set C = F and solve the equation F = 5/9(F -32) this will give the temperature at which they are equal. I will give you a hint. It is very cold.
2007-01-05 07:52:36
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answer #8
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answered by rscanner 6
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At c = 0, you get F-intercept = 32.
At F = 0, you get c-intercept = -160/9
F = 9c/5 + 32
2007-01-05 07:55:51
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answer #9
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answered by sahsjing 7
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c=5/9(f-32) *9
9c=5(f-32)
9c=5f-160 by arrange the equation
5f-9c=160 /160
f/32+c/(-160/9)=1
then f_intercept is 32 &c_intercept is -160/9
2007-01-05 08:13:41
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answer #10
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answered by eissa 3
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