Math Problem..?

Question

Ricardo has 1 3/4(mixed number) times as much money as James. Lucy has 1 2/3(mixed number) as much as Ricardo. How much money does each person have if the total amount of money for all 3 people is $1360?

Answer 1

let the money with james be x
money with ricardo= 1 3/4 times x
=(7/4)x
money withlucy is 1 2/3 times money with ricardo
=(5/3)(7/4)x
=(35/12)x
total money with the three of them is x+(7/4)x+(35/12)x
=[(12+21+35)/12]x=1360 given
68/12x=1360
multiplying by (12/68)
x=1360*12/68=240
so the money with them
james=$240
ricardo=$420
lucy=$700

Answer 2

ALl you need to do is write an equation from words:

1360 = R + J + L
Now, what do we know about R, J, and L.
R = 1 3/4*J
L = 1 2/3 R = 1 2/3 * 1 3/4 * J

So now, 1360 = 1 3/4 J + J + 1 2/3*1 3/4 J
= J(7/4 + 1 + 8/3*7/4) = J*(21/12+12/12+56/12) = J*(89/12)
so J = 1360*12/89
You can do the math to figure out what J is, and then use J to figure out what R and L are.

Answer 3

Let money owned by each of them as $R for Ricardo, $J James and $L for Lucy.

R=(7/4)J also as J=(4/7)R
L=(5/3)R
R+J+L=1360

By substitution,
R+(4/7)R+(5/3)R=1360
(68/21)R=1360
R=420
J=(4/7)(420)=240
L=(5/3)(420)=700

Ricardo has $420, James has $240 and Lucy has $700

Answer 4

Let J be James' amount
Let R be Ricardo's amount
Let L be Lucy's amount

The easiest way is to express everything in terms of James amount:

J = J
R = (7/4)J
L = (5/3)R = (5/3)(7/4)J

Now add them all up:
(7/4)J + (5/3)(7/4)J + J = $1360

The lowest common denominator is 12, so multiply both sides by 12:
21J + 35J + 12J = $1360 * 12

Add up the J terms:
68J = $1360 * 12

Divide both sides by 68:
J = $1360 * 12 / 68
J = 20 * 12
J = $240

James = $240
Ricardo = (7/4)(240) = 7 * 60 = $420
Lucy = (5/3)(420) = 5 * 140 = $700

And as a double-check these amounts ($240 + $420 + $700) do indeed add up to $1,360.

Answer 5

Let amount James has be $j

Therefore Ricardo has $j X 1¾
= $7j/4

And Lucy has $7j/4 X 1⅔
= $7j/4 X 5/3

= $35j/12

So j + 7j/4 + 35j/12 = 1360

Multiply all by LCD of fractions ie 12

So 12j + 21j + 35j = 16320
ie 68j = 16320

So j = 240

ie James had $240
So Ricardo had $240 X 7/4
= $420

And Lucy had $420 x 5/3
= $700

Sum of amounts = $700 + $420 + $240
= $1360 ............. YESSSSSSSSSSSSSSSSSSSSS!!!!!!!!!!!

Answer 6

r=1.75j
l=5/3 r=1.75*5/3 j
j+r+l=1360
j+1.75j+8.75/3 j=1360
3j+5.25j+8.75j=4080
17j=4080
j=4080/17=240 james has $240
r=1.75j=1.75*240=420 Ricardo has $420
l=5/3 r=5/3 420=700 Lucy has $700

check
240+420+700=1360

Answer 7

So, let me try...

First:
R + J + L = 1360
and:
R = 7/4 * J
L = 5/3 * R

So:
R = R
J = R * 4/7
L = R * 5/3

so...
R + J + L = 1360
R + (R * 4/7) + (R * 5/3) = 1360
R * (1 + 4/7 + 5/3 ) = 1360
R * 68/21 = 1360
R = 1360*21/68
R = 420

J = 420 * 4/7 = 240
L = 420 * 5/3 = 700

Hope it helps ;)

Answer 8

total = r + j + l
total = 1.75 x j + j + 1.6667 * r
total = 1.75 x j + j + 2.9167 x j
total = 5.6667 x j

so j = 240
so r = 420
so l = 700

Answer 9

????? i am in 6 th grade math - 7th