For my math hw I received a bunch of problems, but what I'm having problems with is this one; I can't figure out where to go from here:
(5x^3+[0x^2]+4x-1)/2x+3.
Now, I know how to divide polynomials, but I don't know where to go from here as 2x divided into 5x^3 yields 2x^2, and after the subtraction is worked out, you end up with this: x^3-6x^2.
The problem is you must completely divide the the divisor 2x+3 into 5x^3+0x^2, but that cannot be done. I would belive you'd do something along the lines of 2.5x^2, but that doesn't make sense and I think my teacher said something about not being able to do that.
2007-01-05 05:34:42 · 2 answers · asked by BassX 2 in Science & Mathematics ➔ Mathematics
(5x^3+[0x^2]+4x-1)/2x+3.
Yes you can do that. What makes you think you cannot?
The answer is 2.5x^2 - 3.75 x +7.6 with a remainder of -23.8.
2007-01-05 05:45:05 · answer #1 · answered by ironduke8159 7 · 0⤊ 0⤋
My Calculus is a bit rusty, but what the heck? I'm going to give it a shot and if I'm wrong, someone who knows is sure to answer.
(5x^3 + x^2 + 4x -1) / 2x + 3
15x^2 + 2x + 3 / 2x +3
30x + 2 / 2x +3 or 30x/2x + 2/3
15x + 2/3
For those of you who know, is this right?
2007-01-05 13:48:24 · answer #2 · answered by Anonymous · 0⤊ 0⤋