a large block weighs 6x as much as a small black. together they weigh 56. how much does the large box weigh?

Answer 1

Let x be the weight of the small block (or box)
Let 6x be the weight of the large block (or box)

The sum of their weights is 56:
6x + x = 56

Combining like terms:
7x = 56

Dividing both sides by 7:
x = 8

This is the weight of the small box
And the large box is 6 times this or 48.

The small box weighs 8 and the large box weighs 48

Answer 2

So
Let X= small box
Let 6X = big box (since it's in a ratio of 6 to 1)
when u add them together you get 56
6X + X = 56
Combine the like terms
7X = 56
Divide by 7
X = 8
so six * 8 equals 48
Thus the large box weighs 48 units

Answer 3

let small box weigh = X
so large box weigh = 6*X
Together they weigh 56, so:

small + large = 56 or,

X + 6X = 56 and simplified,

7X = 56 now divide both side by 7 to isolate X on 1 side, and

X = 8 which is the weight of the small box; moreover, the large box weigh 6 times of small box, so the large box weighs,

large box : 6 * X or 6 * 8 = 48

Answer 4

If large block = x
and small block = y

From your statement we can say:

i) x = 6y
and
ii) x+y = 56

So, if we rearrange ii)

iii) y = 56-x

Substitute into i)

x = 6(56-x)
= 336-6x

Collect both x terms together to get:

7x = 336

therefore x, the large box = 48 (in whatever units you're using)

I hope that is of some assistance :-)

Answer 5

56 = large block + small block = 6x + x = 7x

So a small block is 56/7 = 8 units and large one is 6*8 = 48 units

Answer 6

Large box weighs 48, because x=8.

Answer 7

48