2007-01-05 03:21:59 · 6 answers · asked by CoNfUsEd 2 in Science & Mathematics ➔ Chemistry
grams = moles x formula mass
First calculate moles = Volume x Conc / 1000 = 235x1.45/1000=0.34075
grams = 0.34075 x 158 = 53.84g
2007-01-05 03:41:32 · answer #1 · answered by LC 3 · 0⤊ 1⤋
grams = Molar concentration x Volume in Liters x Formula weight.
Note: Normality = Molarity x Reacting units/molecule
(Mn+7 ===> Mn+2 + 5 e) In this 1/2 rxn there are 5 reacting units i.e. electrons.
Good Luck
2007-01-05 12:13:27 · answer #2 · answered by docrider28 4 · 0⤊ 1⤋
The normality of a solution is simply a multiple of the morarity of the solution. Since this solution has a factor of one because the formula of the chemical has a cation ion charge of one. Because of that the mole/grams are the same for the molarity solution and normality solution.
53.84g of KMnO4 is needed to prepare your solution
2007-01-05 14:28:19 · answer #3 · answered by bige1236 4 · 0⤊ 1⤋
I think it's 74.48 g.
Mix it with H2O up to the 1M mark.
Then take 235 ml of that.
Please correct me if I'm wrong people.
Peace.
2007-01-05 11:38:18 · answer #4 · answered by in_crueger 2 · 0⤊ 1⤋
Please clarify the concentration units of your solution.
i.e. 1.45 M? 1.45 N? 1.45 mM? What?
(This is what the previous poster means.....)
2007-01-05 11:36:09 · answer #5 · answered by ? 4 · 0⤊ 1⤋
1.45 of wat
2007-01-05 11:23:57 · answer #6 · answered by akshayrangasai 2 · 0⤊ 1⤋