cnx.org/content/m10244/latest
this link contains more then enough
2007-01-05 00:40:48
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answer #1
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answered by Ritesh13171 3
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Well ill start with the basic definition....
Probability is defined as the number of favourable outcomes/Sample space(this is also referred as the classical definition of probability)
We can divide the questions on probability in two broad categories:
1)We have complete knowledge of event(Sample Space)
2)We do not have the sample space(Application of Baye's theorem)
In category 1 we can use the classical definition. Some questions are made easier using permutations and combinations.
In category 2 we use Baye's theorem given by:
P(B/A)=P(B)P(A/B)/P(A)
Where B and A are any 2 events P(A/B) means the probability of occurance of event A given the event B has occured.
P(A) in the above equation can be calculated by total probability theorem.
In some cases we find it hard to calculate the probability due to greater number of occurances,we use binomial distribution given by:
nCr*p1^r*p2^n-r
where n and r are number of times the events occur and nCr has its usual meaning.
For even larger occurances we use Poiisson's ratio,Im sorry i dont have sufficient knowledge about it!
2007-01-05 03:16:36
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answer #2
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answered by Anonymous
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Thanks, I'll take three.
It would probably help your cause to ask more specific questions. However, assuming that you would like to know some of the fundamental equations of probability, here they are:
P(A ∩ B) = 0 for mutually exclusive events
P(A ∩ B) = P(A).P(B) for independent events
(these two are more definitions of mutually exclusive and independent events than equations as such, but they are important).
P(A ∪ B) = P(A) + P(B) - P(A ∩ B)
or equivalently
P(A ∩ B) = P(A) + P(B) - P(A ∪ B)
or equivalently
P(A ∩ B) + P(A ∪ B) = P(A) + P(B)
Conditional probability:
P(A | B) = P(A ∩ B) / P(B)
from which we can derive Bayes' Theorem:
P(A | B) = P(A) . P(B | A) / P(B)
And that's about it.
2007-01-04 22:53:29
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answer #3
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answered by Scarlet Manuka 7
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I cant supply you with an equation, yet i'm able to grant some good judgment. If stated incidence happens a million in a million, it may rely of the lapse of time between each and every experience on in spite of if or not increasing the span of time measured could boost the percentages of the regarded for experience to happen. Does that make experience? it form of feels that there is a factor of the information lacking to supply a correct answer
2016-12-12 04:19:34
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answer #4
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answered by Anonymous
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P(event) = (number of equally likely ways the event can happen)/ (total number of equally likely outcomes)
P(A or B) = P(A) + P(B) - P(A and B)
P(A and B) = P(A)*P(B/A) Note P(B/A) means Prob of B given that A has already occurred.
2007-01-04 22:52:51
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answer #5
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answered by Hy 7
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Probility (p)= No. of desired outcomes /no.of possible outcomes
for mutually Exclusive Events:
P(A or B)=P(A)+P(B)
for independent events:
P(A and B)= P(A)*P(B)
Conditional probility:
P(A/B)=P(A and B)/P(B)
2007-01-04 23:17:25
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answer #6
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answered by Anonymous
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number of favourable conditions to the total numberof outcomes
2007-01-04 22:55:11
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answer #7
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answered by raja 1
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PROBABILITY MEANS POSSIBILITIES. THERE IS ONE EASIEST FORMULA TO SOLVE THE QUESTIONS THAT IS
PROBABILITY=FAVOURABLE CASES/ TOTAL CASES.
2007-01-05 18:22:11
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answer #8
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answered by Anonymous
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watch this animated mini movie...http://www.brainpop.com/math/dataanalysisandprobability/basicprobability/
2007-01-04 22:49:57
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answer #9
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answered by tonima 4
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go to mathworld.wolfram.com
2007-01-06 04:23:30
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answer #10
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answered by mundane gal 2
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