a man undertakes a work in 150days,employs 200workers&only a 1/4 of work done in 50days.how much man needed to

Question

please provide me the method solving the following problem: a man undertakes to do a work in 150days, he employs 200workers & found only a 1/4th of work done in 50days. in order to complete the work in scheduled time of 150 days, how much additional worker needed to be employed?

Answer 1

The solution is:
Initially 200 workers,50 days,1/4 of work.
Remaining work can be done by employing some extra workers so 200+x workers,100 days,3/4 work left.
So by Time and work we can equate the equations by,
(200*50)/(1/4)={(200+x)*100}/(3/4)
solving this gives Value of x=100.
So additionally 100 workers are needed to complete the work

Answer 2

1) 200 workers X 50 days = 10000 man-days of work
2) In other words, 1/4 requires 10000 man-days of work, right?
3) So, 3/4 work will require 3 X 10000 = 30000 man-days of work.......
I multiplied by 3 because 3/4 is 3 times 1/4.
4) Now, there are 100 days remaining.
5) So, workers required = 30000/100 = 300
6) But remember, we already have 200 of them
7) So, additional workers reqd = 100

Answer 3

This is a sexual discrimination issue. What is wrong with employing a woman?