2007-01-04 19:44:51 · 4 answers · asked by Anonymous in Science & Mathematics ➔ Chemistry
as boron do not have vacant d orbital+the size of Cl is very large
2007-01-04 19:48:08 · answer #1 · answered by ISAEINS 3 · 0⤊ 1⤋
Boron is a group three element that only forms 3 bonds. You could possibly have BCl3. Plus B is quite small and Cl is pretty large, so even if it could form a fourth bond, which it can't, there would be a lot of strain from overlapping van der waals radii.
What is "ACl4"? Is that supposed to be AlCl4?
Metals have more complex valencies than non-metals. As you know, they have different oxidation states and can form different numbers of bonds depending on the oxidation state.
2007-01-05 03:55:51 · answer #2 · answered by Nick B 3 · 0⤊ 0⤋
BCl3 and AlCl3 are electron-deficient compounds, with 6 electrons in the outer level of the central atom. They can therefore act as Lewis acids, and, in theory, could accept a Cl- ion in order to complete their valency octets. However, there is no room around the B atom in BCl3 for a 4th chlorine, whereas Al, being so much bigger, does have some space.
2007-01-05 07:32:04 · answer #3 · answered by Gervald F 7 · 0⤊ 0⤋
because the size of boron is too small to hold four bulky chlorine together. How can you expect a rabbit to carry four bulky suitcases????
2007-01-05 03:54:38 · answer #4 · answered by Anonymous · 1⤊ 1⤋