What is the center of the circle given (x + 4)2 + (y + 3)2 = 64
2007-01-04 17:25:35 · 6 answers · asked by monica 1 in Science & Mathematics ➔ Mathematics
(-4,-3)
2007-01-08 17:28:31 · answer #1 · answered by Anonymous · 0⤊ 0⤋
Compare to the standard equation of a circle,
(x + 4)^2 + (y + 3)^2 = 64 is the same as
(x - -4)^2 + (y - -3)^2 = 8^2
Therefore, the center is at (-4, -3).
2007-01-04 17:30:02 · answer #2 · answered by sahsjing 7 · 0⤊ 0⤋
It's the point (-4,-3)
2007-01-04 23:52:03 · answer #3 · answered by steiner1745 7 · 0⤊ 0⤋
HAHA, i thought those 2s outside the brackets were multiply...next time indicate the exponent with ^
centre ( -4, -3 )
and yes CENTRE, im canadian
2007-01-04 17:29:27 · answer #4 · answered by Donny Dutch 4 · 0⤊ 0⤋
centre is (-4,-3)
raius is 8 units
2007-01-04 17:28:10 · answer #5 · answered by raj 7 · 0⤊ 0⤋
x+4=0
x=-4
y+3=0
y=-3
center(-4,-3)
2007-01-04 17:34:59 · answer #6 · answered by iyiogrenci 6 · 0⤊ 0⤋