Which equation corresponds to the circle with center (2, -3) and radius = 5?
What is the center of the circle given (x + 4)2 + (y + 3)2 = 64
2007-01-04 17:05:12 · 5 answers · asked by monica 1 in Science & Mathematics ➔ Mathematics
The second one, the center is (-4, -3), and the radius is 8.
From that, work backwards and figure the equation for the first one.
2007-01-04 17:10:53 · answer #1 · answered by powhound 7 · 0⤊ 0⤋
Which equation corresponds to the circle with center (2, -3) and radius = 5?
(x - 2)^2 + (y + 3)^2 = 25
What is the center of the circle given (x + 4)2 + (y + 3)2 = 64
(-4, -3)
2007-01-04 17:26:21 · answer #2 · answered by Helmut 7 · 0⤊ 0⤋
Generally the equation for a circle is (x-h)+(y-k)=r^2 where (h,k) is the center and r is the radius. **note that h and k are *opposite* the sign that precedes them in the equation. Therefore the answer to the first question would be
(x-2)+(y+3)=25
and the answer to the second would be
center: (-4,-3) and radius:square root of 32
2007-01-04 17:17:59 · answer #3 · answered by C from USA 1 · 0⤊ 0⤋
The desired circle is (x-2)^2 + (y+3)^2 = 25
The center of the circle given is (-4, -3) (and the radius is 8)
In general, a circle defined by (x-a)^2 + (y-b)^2 = r^2
has radius r and center (a,b)
2007-01-04 17:11:46 · answer #4 · answered by Anonymous · 0⤊ 0⤋
(x-2)^2+(y+3)^2=5^2
2.centre(-4,-3)
radius=8
2007-01-04 17:19:53 · answer #5 · answered by raj 7 · 0⤊ 0⤋