find the area of parallelogram whose dimensions are given?

Question

AB= 9.5
BD= 27
CD= 9.5
AC= 27

Answer 1

Yeah, Raj noticed something is wrong.

There isn't enough information. You need another length given, or an angle.

Please double check your problem.

Answer 2

I am assuming that the 4 corners are sequential - in other words, the sides run from A > B > C > D > A.

If this is true, then wew have the dims for the 2 diagonals, namely BD and AC, both of which are given to be 27. Since the two diagonals are equal, the parallelogram is a rectangle, and we have he length of the two opposing sides, which are equal.

We can now divide the parallelogram into 2 right-angled triangles, and use Pythagoras to find the two missing (and equal in length) sides:

a² + b² = c²

Let's call AB a, which leaves b unknown, and c is then AC.

9.5² + b² = 27²
b² = 27² - 9.5²
b² = 729 - 90.25
b² = 638.75
b = SqR (638.75) = 25.2735

Now that we have the remaining side, the area is easy to find, since a rectangular parallelogram's area is simply the multiple of two of it's sides:

a * b = area

9.5 * 25.2735 = 240.0983

That ought to do it.
What is this for?
Are you doing homework?

Answer 3

It is a rectangle. Therefore,
area = width x height
= (9.5)√[27^2-9.5^2]
= 240.098

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Nothing wrong in the original problem. It must be a rectangle under the requirements: parallelogram plus a pair of congruent opposite sides and congruent diagonals.

Answer 4

It is NOT POSSIBLE
Because the area of a parallelogram is also depened on the angles.

Try to construct a parallelogram with given dimenssions, you can contruct tons of them with different angles between them.

Answer 5

form a rectangular from paralelogram
h^2=27^2-9,5^2
=17,5*36,5
=636,75

h=25,23

area=9,5*25,23/2=119,84

Answer 6

0 ≤ A ≤ 256.5

Answer 7

something wrong withthe sum.please post again