is a triangle with sides of lengths 20, 21 and 29 a right triangle?
2007-01-04 16:42:44 · 7 answers · asked by sweet-chic 1 in Science & Mathematics ➔ Mathematics
Yes, it is since
20^2 + 21^2 = 29^2 (=841)
The Pythagoras theorem is true for this case. The hypotenuse is the side with length 29 units.
2007-01-04 16:48:27 · answer #1 · answered by techieguy 4 · 0⤊ 0⤋
Test is by seeing if 20^2 + 21^2 = 29^2 If that is not true then it is not a right triangle
2007-01-05 00:48:10 · answer #2 · answered by rscanner 6 · 0⤊ 0⤋
Yes, because it fits the Pythogrean formula
20*20 + 21*21 = 29*29
That's all you need.
Generally, if the sides are A, B, and C, with C being the longest, this will be a right triangle if and only if A*A + B*B = C*C
2007-01-05 00:47:24 · answer #3 · answered by Anonymous · 1⤊ 0⤋
in a right angled triangle the square of hypotenuse is equal to the sum of squares of other two sides(theorem of pythagoras).
as hypotenuse is longest side. 29 is hypotenuse.
since ,
29^2= 20^2 + 21^2
841= 400 + 441
= 841
there fore it follows pythagoras theorem and hence the triangle is a right angled triangle
2007-01-05 01:38:28 · answer #4 · answered by supermind1990 1 · 0⤊ 0⤋
Yes. Use the Pythagorean Theorem.
20² + 21² = 29²
So it is.
2007-01-05 01:13:18 · answer #5 · answered by Northstar 7 · 0⤊ 0⤋
20² = 400
21² = 441
-------------
29² = 841
yes, by Pythagoras!
2007-01-05 00:48:49 · answer #6 · answered by Philo 7 · 0⤊ 0⤋
nope
2007-01-05 00:45:13 · answer #7 · answered by hgghhfhgfjh 1 · 0⤊ 2⤋