Can you simplify this?

Question

y^10/2x^3 * 20x^14/xy^6

Please show all work!

I don't understand the second answer can someone please explain it to me?

Answer 1

Try using natual logs, whats the RHS.... Zero?

Answer 2

I don't know if the parentheses are needed, but I'm interpreting
y^10/2x^3 * 20 x^14 / xy^6 =

y^10 / (2 x^3) * 20 x^14 / (xy^6). If this is true, then you have:

20/ 2 * y^(10 -6) * x^(14 - 1 - 3) = 10 y^4 x^10

Answer 3

Mulitply across the top and bottom:

y^10*20x^14
----------------
2x^4y^6 -- remember, if the bases are the same, when you multiply you add the exponents, so x^3*x = x^4

Now you can cancel y^10 with y^6. Much like you added the powers to multiply, you subtract them when you divide. so 10-6 = 4, so that leaves y^4 in the top. 20/2 = 10, and x^14/x^4 = x^10

So you're left with 2x^10y^4

Answer 4

y^10/2x^3 * 20x^14/xy^6
= (2*20/10)(x^-3*X^14*X)(Y^10* Y^-6)
= 4X^12Y^4
that is categories the some variables then do the math

Answer 5

y^10/2x^3*20x^14/xy^6
=20*x^14*y^10/2x^4*y^6
=10*x^14-4*y^10-6
=10*x^10*y^4