If the entire known universe were filled with water, how many gallons would comprise it?
2007-01-04 14:51:39 · 16 answers · asked by tavives 2 in Science & Mathematics ➔ Mathematics
Okay,
7.48 gallons per cubic foot
5.28 *10^3 feet per mile
5.87 * 10^12 miles per light year
1.56 * 10^11 light years across "known universe" (see link)
So, answer is roughly
(7.48)*
((5.28*10^3) (5.87*10^12) (1.56*10^11))^3
gallons, or approximately
10^86 gallons
2007-01-04 16:58:05 · answer #1 · answered by Scythian1950 7 · 1⤊ 0⤋
What a time waster. Here goes:
1. Filled with water with no black holes? Because if there were black holes all of the water would be sucked into them throwing the calculation off.
2. Speaking of compression, wouldn't the water compress?
3. I am not astrophysicist, but I think the water would begin to fuse as it heated up during compression and you would form something like one universal size sun
4. So, lets say the universe became empty and then filled up with water. For the first fraction of a nano-nano second what would be the volume in gallons?
Assuming an inflationary model, you need to get the current estimated diameter of the universe, divide by two to get the radius and then use the old formula V=4/3*pi*r^3
Of course its volume is changing since the radius is increasing by much over 186,000 miles every second (what with dark energy). so if you know r in light years, and that there are 31 million seconds in a year and there are 186,000 miles is a light second and there are 5280 feet in a mile you can figure how many cubic feet are in a cubic light-year, then convert cu.ft. to gallons (US fluid). In the time it took me to write this the universe expanded by more than the entire volume of all the water in it probably by many times that much.
2007-01-04 15:21:30 · answer #2 · answered by Anonymous · 1⤊ 0⤋
i am not so good with gallons but here goes the volume of the place in the universe where all the stuff is, that i call the hyperluminosphere, is 3.966771422 to the exponent of 110 cubic meters. it has a vergocentric radius of 4.54128 to the exponent of 27 meters. it all has a mas of 4 to the 52nd killograms and at its outermost edge an escape velocity that is eactly 2c or 2 times the speed of light. this measurement has stood since 1999 when i made the measurement.
darn there goes the calculator batery agean.
to get the volume in galons from a kiloliter multiply the kiloliter by
264.2
2007-01-04 15:44:25 · answer #3 · answered by wildratsci 1 · 1⤊ 0⤋
We wouldn't be able to keep track of something like that.Plus I don't think we would have enough water to fill the entire known universe.
2007-01-04 14:57:54 · answer #4 · answered by debralizjr 4 · 1⤊ 0⤋
I don't think this has ever been calculated, mainly because our understanding of measurements on such a scale is null. How do you come up with a volume for an area that has no width or height?
2007-01-04 14:54:48 · answer #5 · answered by Benton 3 · 1⤊ 0⤋
The Universe is NOT known and therefore your question has no answer!
2007-01-04 15:15:35 · answer #6 · answered by Nikolas S 6 · 1⤊ 0⤋
There isn't a number large enough to describe the amount of water required...
2007-01-04 14:54:49 · answer #7 · answered by ropman1 4 · 1⤊ 0⤋
Unanswerable.
1) we don't know the size of the universe
2) you didn't say what temperature and pressure the water would be at, so we can't determine if it would be solid, liquid, or gas.
2007-01-04 14:58:30 · answer #8 · answered by C. C 3 · 1⤊ 0⤋
6 gallons?
2007-01-04 14:59:06 · answer #9 · answered by Anonymous · 0⤊ 1⤋
It would be too hard to tell considering the person doing the measuring would probably drown.
...just my two cents.
2007-01-04 14:58:45 · answer #10 · answered by aficionado210 2 · 1⤊ 0⤋