The polynomial is -3x^3+x^2+17+6x^4.
Please help.
2007-01-04 14:14:51 · 4 answers · asked by Random G 3 in Science & Mathematics ➔ Mathematics
the standard form would be f(x)=6x^4 - 3x^3 + 1x^2 + 0x + 17,
There would be five coefficients; 6, -3, 1, 0, and 17.
The coefficients are also called the constants of the polynomial.
2007-01-04 14:22:27 · answer #1 · answered by christopher_az 2 · 0⤊ 0⤋
The complete form is
6x^4 - 3x^3 + 1x^2 + 0x + 0
A coefficient is a number in front of the 'x'.
So there are 4 coefficients: 6, -3, 1, and 0. =)
2007-01-04 22:17:59 · answer #2 · answered by teekshi33 4 · 0⤊ 0⤋
The coefficient is the number that comes before the variable (or letter). Therefore the coefficients are:
-3, 1,3
This is a fourth order equation because the highest power on x is 4.
2007-01-04 22:19:24 · answer #3 · answered by Dalonna 2 · 0⤊ 1⤋
no. there are two. the plus o thing. no not working. there could be an infintate number of plus o and times 1's. there are two. those are negative three and six.
2007-01-04 23:36:28 · answer #4 · answered by Lindsay Lee 2 · 0⤊ 0⤋