what is the square root of 8z^2y^3?

2 ⤊

what is the square root of 8z^2y^3?

2007-01-04 13:47:08 · 3 answers · asked by tweety b 1 in Science & Mathematics ➔ Mathematics

3 answers

sqrt(8z^2y^3)
=sqrt(8)(z)(y^3/2)
=sqrt(4x2)(z)(y^3/2)
=2 sqrt(2) (z) (y^3/2)

2007-01-04 13:57:32 · answer #1 · answered by seah 7 · 1⤊ 0⤋

The former answerers forgot to use the absolute value from z. The rest is right

sqrt can be written so: sqrt (4*2) = sqrt 4* sqrt 2 = 2 sqrt2

And y^(3/2) can be written too so: sqrt (y^3)

DON'T FORGET THAT SQRT (Z^2) IS ABSOLUTE VALUE FROM Z, lzl or abs (z)

Anabel

2007-01-04 21:57:33 · answer #2 · answered by Anonymous · 0⤊ 0⤋

sqrt(8)*Z*y^(3/2)

2007-01-04 21:51:06 · answer #3 · answered by The Q Meister 2 · 1⤊ 0⤋