The cheerleading team bought five bags of apples to sell at a track meet. Each bag cost $3.20 and had an average of eight apples. The team sold the apples for 75 cents each. All but six of the apples were sold. What was the team's profit?
2007-01-04 13:25:49 · 5 answers · asked by kk k 1 in Science & Mathematics ➔ Mathematics
well, start with what they lost. they bought 5 bags each worth $3.20-- that comes to a cost of $16.
if we can say each bag had 8 apples, and there were 5 bags, then there were 40 apples total, and 34 then were sold. if each was sold for $0.75, you multiply 34 times 0.75, and the money they made was $25.50. so 25.50 - 16 dollars initial loss, equals 9.5.
they made $9.50 in all for profits
2007-01-04 13:31:58 · answer #1 · answered by car of boat 4 · 1⤊ 0⤋
Five bags * $3.20/bag = $16 total spent.
Average of 8 apples/bags gives a total of 40 apples.
40 - 6 - 34 were sold at 75 cents each, so they made 34 * .75 = $25.50
Therefore, 25.50 - 16 = $9.50 profit.
2007-01-04 21:34:07 · answer #2 · answered by JasonM 7 · 0⤊ 0⤋
Profit = revenue - expense
Expense is $3.20*5 = $16
Revenue: Each bag held 8 apples, so 8*5 = 40 apples. 40-6 = 34 apples sold at $.75 = $25.50
So profit = $25.50 - $16 = $9.50
2007-01-04 21:33:15 · answer #3 · answered by hunneebee22 4 · 0⤊ 0⤋
$3.20x5=$16.00=8x5=40 apples 40apples-6=34 apples x.75=$25.50 $25.50-16.00=$9.50
2007-01-04 21:52:09 · answer #4 · answered by pc187 2 · 0⤊ 0⤋
total no of apples=40
cost=$16.0
selling price=34*0.75
=$25.50
profit=$9.50
2007-01-04 21:32:14 · answer #5 · answered by raj 7 · 1⤊ 0⤋