5x+y=50
x+y=22
4x=28
x=7
y=15
so 7 $5 bills and 15 $1 bills
2007-01-04 13:20:30
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answer #1
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answered by raj 7
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There are 22 bills in all
So, F + U = 22 --- (1)
Also, the values of F and U are 5:1
So, 5F + U = 50 --- (2)
Eqn (2) - (1)
=> (5F+U) - (F+U) = 50 - 22
=> (5F - F) + (U - U) = 28
=> 4F = 28
=> F = 7
F + U = 7 + U = 22
U = 22 - 7 = 15
You can confirm this way
Total no. of bills = 15 + 7 = 22
Total value = 15 * 1 + 5 * 7 = 50
2007-01-04 13:27:52
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answer #2
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answered by upkar k 2
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okay, F will be the amount of five dollar bills you have; U will be the amount of one dollar bills you have.
F + U = 22 (you get that since there are 22 bills total)
5F + 1U = 50 (now you give weight to each bill-- with each five dollar bill, you get five dollars worth-- makes sense?)
now, substitute one variable for the other. U = 22 - F, which you can plug into the second equation.
5F + 1(22-F) = 50
5F - F + 22 =50
4F = 28
F = 7 --> means there's seven $5-bills. and since there are 22 total, that means there's 15 one-dollar bills.
2007-01-04 13:23:18
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answer #3
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answered by car of boat 4
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5F+1U=50
$5 times number of $5 bills + $1 times number of singles equals $50
F+U=22
Number of $5 bills + number of singles = 22 bills
U=22-F [Subtract F from both sides]
5F+1(22-F)[From first equation] = 50
5F + 22 - F = 50
4F + 22 = 50
4F = 28
F = 7
So, you have 7 Five Dollar bills, so the rest (22-7) are 1 Dollar Bills
So you have 7 $5 Bills and 15 $1 Bills
2007-01-04 13:24:46
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answer #4
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answered by JP 2
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7 five dollar bills=$35 and 15 one dollar bills= $15 so that equals $50 and 7+15=22 so theres your answer
2007-01-04 13:24:47
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answer #5
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answered by Tink* 2
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You have two equations.
F + U = 22
5F + U = 50
Subtracting we get:
4F = 28
F = 7
U = 22 - F = 22 - 7 = 15
So you have 7 five dollar bills and 15 one dollar bills.
2007-01-04 13:28:11
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answer #6
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answered by Northstar 7
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7 five dollar bills and 15 one dollar bills
2007-01-04 13:20:53
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answer #7
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answered by blaine m 2
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u+f=22 (for number of bills)
u+5f=50 (for dollr amt)
4f=28, so f=7
7 fives and 15 ones
2007-01-04 13:22:03
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answer #8
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answered by ray 3
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15 one dollar bills
7 five dollar bills
2007-01-04 13:20:07
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answer #9
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answered by aznwangstaaa 2
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2 a thank you to sparkling up: #a million: removal x+2y=0 2x-6y=5 Multiply equation a million via 3 3x+6y=0 2x-6y=5 -----------upload 5x=5 x=a million replace a million for x into the two of the two unique equations. x+2y=0 a million+2y=0 2y=-a million y= -a million/2 #2: Substitution x+2y=0 2x-6y=5 From Equation No.a million, x=-2y replace x with -2y in Equation No.2 2(-2y)-6y=5 -4y-6y=5 -10y=5 y= -a million/2 As earlier, replace y with -a million/2 in the two unique equation. 2x-6y=5 2x-6(-a million/2)=5 2x+3=5 2x=2 x=a million Take your %.!
2016-10-06 11:06:46
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answer #10
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answered by ? 4
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