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Juan goes to a bank and gets change for a $50 bill consisting of all $5 bills and $1 bills. There are 22 bills in all. How many of each kind are there?

In this problem ill make F= Five dollar bills.
and U= One dollar bills.

ive done every other problem except for this one.
Please help !

2007-01-04 13:17:55 · 12 answers · asked by skatebaker416 1 in Science & Mathematics Mathematics

12 answers

5x+y=50
x+y=22
4x=28
x=7
y=15
so 7 $5 bills and 15 $1 bills

2007-01-04 13:20:30 · answer #1 · answered by raj 7 · 0 0

There are 22 bills in all
So, F + U = 22 --- (1)

Also, the values of F and U are 5:1
So, 5F + U = 50 --- (2)

Eqn (2) - (1)
=> (5F+U) - (F+U) = 50 - 22
=> (5F - F) + (U - U) = 28
=> 4F = 28
=> F = 7

F + U = 7 + U = 22
U = 22 - 7 = 15


You can confirm this way
Total no. of bills = 15 + 7 = 22
Total value = 15 * 1 + 5 * 7 = 50

2007-01-04 13:27:52 · answer #2 · answered by upkar k 2 · 0 0

okay, F will be the amount of five dollar bills you have; U will be the amount of one dollar bills you have.

F + U = 22 (you get that since there are 22 bills total)
5F + 1U = 50 (now you give weight to each bill-- with each five dollar bill, you get five dollars worth-- makes sense?)
now, substitute one variable for the other. U = 22 - F, which you can plug into the second equation.
5F + 1(22-F) = 50
5F - F + 22 =50
4F = 28
F = 7 --> means there's seven $5-bills. and since there are 22 total, that means there's 15 one-dollar bills.

2007-01-04 13:23:18 · answer #3 · answered by car of boat 4 · 0 0

5F+1U=50
$5 times number of $5 bills + $1 times number of singles equals $50
F+U=22
Number of $5 bills + number of singles = 22 bills
U=22-F [Subtract F from both sides]
5F+1(22-F)[From first equation] = 50
5F + 22 - F = 50
4F + 22 = 50
4F = 28
F = 7
So, you have 7 Five Dollar bills, so the rest (22-7) are 1 Dollar Bills

So you have 7 $5 Bills and 15 $1 Bills

2007-01-04 13:24:46 · answer #4 · answered by JP 2 · 0 0

7 five dollar bills=$35 and 15 one dollar bills= $15 so that equals $50 and 7+15=22 so theres your answer

2007-01-04 13:24:47 · answer #5 · answered by Tink* 2 · 0 0

You have two equations.

F + U = 22
5F + U = 50

Subtracting we get:

4F = 28
F = 7

U = 22 - F = 22 - 7 = 15

So you have 7 five dollar bills and 15 one dollar bills.

2007-01-04 13:28:11 · answer #6 · answered by Northstar 7 · 0 0

7 five dollar bills and 15 one dollar bills

2007-01-04 13:20:53 · answer #7 · answered by blaine m 2 · 0 0

u+f=22 (for number of bills)
u+5f=50 (for dollr amt)

4f=28, so f=7

7 fives and 15 ones

2007-01-04 13:22:03 · answer #8 · answered by ray 3 · 0 0

15 one dollar bills
7 five dollar bills

2007-01-04 13:20:07 · answer #9 · answered by aznwangstaaa 2 · 0 0

2 a thank you to sparkling up: #a million: removal x+2y=0 2x-6y=5 Multiply equation a million via 3 3x+6y=0 2x-6y=5 -----------upload 5x=5 x=a million replace a million for x into the two of the two unique equations. x+2y=0 a million+2y=0 2y=-a million y= -a million/2 #2: Substitution x+2y=0 2x-6y=5 From Equation No.a million, x=-2y replace x with -2y in Equation No.2 2(-2y)-6y=5 -4y-6y=5 -10y=5 y= -a million/2 As earlier, replace y with -a million/2 in the two unique equation. 2x-6y=5 2x-6(-a million/2)=5 2x+3=5 2x=2 x=a million Take your %.!

2016-10-06 11:06:46 · answer #10 · answered by ? 4 · 0 0

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