Determine the formula of the hydrate that has: 1) 0.907g SrC2O4 and 0.0930g H2O?

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Answer 1

Strontium Oxalate Monohydrate

SrC2O4.H2O

MW of SrC2O4 is 87.6 + 24 + 64 = 175.6
MW of H2O is 16 + 2 = 18

0.907g of SrC2O4 is 0.907/175.6 mole, or 0.0052 mole
0.0930g of H2O is 0.0930/18 mole, or 0.0052 mole.

The ratio is one mole SrC2O4 per mole of H2O, so it's the monohydrate.