A body moves such that its displacement from an origin O at time t seconds is x metres, where x = 4 sin 2t. How far does the body move in the first second?
The working I got from my textbook is:
When t = 0, x = 0
When t = 1, x = 4 sin 2
= 3.64
But when t = π/4, x = 4.
Thus the distance travelled in the first second is 4+ (4-3.64) = 4.36m.
My question is: since I'm asked to find the distance of the body in the first second, should I just sub t = 1 into the equation and leave it at that? Why do I have to also sub t = π/4 into the equation? I also don't understand the rest of the working (i.e. 4+ (4-3.64) = 4.36m)? Help! Thanks in advance!
2007-01-04
12:01:57
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2 answers
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asked by
delye56
2
in
Science & Mathematics
➔ Mathematics