Math Problem again can anybody help.?

Question

The length of a rectangle is 6cm more than twice the width. If the perimeter is 56 cm, find the dimensions of the rectangle.

Answer 1

2h+2l=p
2h+2(h+6)=p
2h+2(h+6)=56
4h+12=56
4h=44
h=11
the height is 11 cm, the width is 17 cm.

Answer 2

Let "x" = the width

then 2 x + 6 = length

2(2x +6) + 2x = 56

4x + 12 + 2x = 56

6x = 56 - 12

6x = 44

x = 7 1/3

Therefore the length = 7 1/3 + 7 1/3 + 6

Length = 14 2/3 + 6 = 20 2/3 cm (answer)

width = 7 1/3 cm

check: 2(20 2/3) + 2(7 1/3)

= 41 1/3 + 14 2/3

= 56 = perimeter in question

Answer 3

Let P = perimeter, L= length, and W=width.

P = 2L + 2W
The given information is that L = 2W + 6 and that P = 56.
Plugging that into the original equation for perimeter,
P=2L + 2W
56 = 2(2W+6) + 2W
As you can see, the expression to which the given information equated the length can be substituted for the actual variable and now we have an equation with one variable than we can solve using simple algebra.

Distributing -- 56 = 4W + 12 + 2W
Combine like terms -- 56 = 6W + 12
Subtract 12 from both sides -- 44 =6W
Divide both sides by six -- 7 and 1/3 cm = W

We have the dimension for width which we can plug back into the give information equation:

L = 2W + 6
L = 2(7 1/3) + 6
L = 14 2/3 + 6
L = 20 and 2/3 cm

Answer 4

The length of the rectangle is 6cm more than twice the width
2W + 6 = L
The perimeter is 56cm
2L + 2W = 56

2(2W + 6) + 2W = 56
4W + 12 + 2W = 56
6W = 44
W = 44/6 = 7 1/3cm

2*(7 1/3) + 6 = L
14 2/3 + 6 = L
L = 20 2/3cm

W = 7 1/3cm
L = 20 2/3cm

Answer 5

x+x+6=56/2

Answer 6

you're completely happening the marvelous way. it seems kinda complicated because of the fact it would not look as in case you may element something appropriate away (which might help to resolve for x). yet yet another approach you need to use to resolve for x is with the aid of employing the easy Theorem of Algebra. incredibly, you will discover the basis in a function that has an n degree of a minimum of a million. to discover such root, you look into the premier coefficient, to that end a million (because of the fact it is x^3), and additionally on the coefficient with n degree of 0, your consistent, to that end -12. next you record the climate of one and all of them a million: +- a million ----we can call a million q -12: +-a million, +-2, +-3, +-4, +-6, +-12 ----we can call -12 p next you plug interior the attainable strategies p/q into the function x^3 + x^2 - 12 , and discover which one =0. word your attainable strategies are p/q = +-a million, +-2, +-3, +-4, +-6, +-12 in case you plug them in, you 'll discover that 2 is your answer.

Answer 7

x+6=2y
2x+2y=56

length=x
width=y

so x+y=28
( 28-y)+6=2y
34-y=2y
34=3y
y=11 1/3

2x+22 2/3 = 56
2x=33 1/3
x= 16.5+ 1/6 = 16 4/6 = 16 2/3

Answer 8

use algebra. let x be the width. (w=x) the length then must be 2x+6. (l=2x+6) since the equation for perimeter is 2l+2w=p, plug in your knowns and solve for x. once you have x solved for, plug it back into the 2x+6 part to find the length.

Answer 9

let l be one side and s be the other

2l+2w = 56

l = 6+2w

2(6+2w) + 2w = 56

12 + 6w = 56

6w = 44

w = 22/3

l=6 + 2(22/3)

l=62/3

Answer 10

I am very impressed Tom.