Guess the #. If i add half of the #, a fourth of the # and a ninth of the # together, I get a total of 62.?

Answer 1

(1/2)x + (1/4)x + (1/9)x = 62

Distribute out an x:
(1/2 + 1/4 + 1/9)x = 62

Now get a common denominator of 36:
(18/36 + 9/36 + 4/36)x = 62

Add the numerators together:
(31/36)x = 62

Now multiply both sides by 36/31
x = 62(36/31)

Cancel out a 31:
x = 2(36)
x = 72

As a double-check:
Half of 72 = 36
A fourth of 72 = 18
A ninth of 72 = 8

36 + 18 + 8 = 62

So the answer is the number is 72

Answer 2

Let x be "the number". Then

(1/2)x + (1/4)x + (1/9)x = 62.

Factoring out an x,

x[1/2 + 1/4 + 1/9] = 62

Multiplying both sides by 36, we get

36x [1/2 + 1/4 + 1/9] = 2232

Let's distribute the 36 over the brackets, leaving the x outside.

x[18 + 9 + 4] = 2232
x[31] = 2232
31x = 2232

Therefore, dividing both sides by 31,

x = 72

Note: It's always a good idea to work with exact fractions instead of calculator approximations.

Answer 3

the number is 72

36+18+8=62

Answer 4

x = some number

x/2 + x/4 + x/9 + 62.

multiply both sides by 36.

18x + 9x + 4x = 2232

31x = 2232

x = 72