I know that the answer to the question is 648 because I've already taken the pretest but I have no idea how to solve this equation. I think I'm doing something wrong. If anyone could help solve this so I know how when it comes up on the real test it will be really appreciated.
2007-01-04 08:00:17 · 8 answers · asked by ? 1 in Science & Mathematics ➔ Mathematics
Thank everyone for there I help. I realized what I was doing wrong and it was really simple. Once I seen it I was like duh! Thanks for all the help!!!
2007-01-04 08:48:02 · update #1
y^3(y^3 - y)
First: replace 3 with the "y" variables >
(3^3)(3^3 - 3)
Sec: solve according to order of operations >
27(27 - 3)
27(24)
648
2007-01-04 08:06:44 · answer #1 · answered by ♪♥Annie♥♪ 6 · 1⤊ 0⤋
3^3=27
27(27-3)=27*24=648
2007-01-04 16:03:19 · answer #2 · answered by hamthugger 4 · 2⤊ 0⤋
do the stuff in the parentheses
y3=27
27-3=24
27(24)
that equals 648
2007-01-04 16:05:37 · answer #3 · answered by Anonymous · 1⤊ 0⤋
3^3((3^3)-3) = 27*(27-3) = 27*24 = 648
2007-01-04 16:05:50 · answer #4 · answered by The Alchemist 2 · 1⤊ 0⤋
3x3x3=27 (Y3) (3x3x3minus3)=24 so, 27(27-3)=27x24=648
2007-01-04 16:13:25 · answer #5 · answered by bailingwirewillfixit 3 · 1⤊ 0⤋
3^3(3^3-3)>
27(27-3)>
27(24)=648
2007-01-04 16:04:08 · answer #6 · answered by louis504842 2 · 2⤊ 0⤋
(3^3)((3^3)-3)
27*(27-3)
27*24=648
2007-01-04 16:23:15 · answer #7 · answered by Anonymous · 0⤊ 0⤋
its so obvious; just substitute all the Y's with 3 and do the math
2007-01-04 16:08:53 · answer #8 · answered by karma 7 · 1⤊ 0⤋