How high will a .325 kg rock go if thrown up by 115 J of work done on it?

Question

How high will a .325 kg rock go if thrown up by 115 J of work done on it?

HELP EXPLAIN!

Answer 1

At the top of the arc, all of the energy that has gone into the rock (115J) has become gravitational potential energy. The equation for gravitational potential energy is:
PE = mgh where m is the mass, g is the gravitational constant (9.8 m/s2), and h is the height.
115 J = (.325 kg)(9.8 m/s2)(h)
h = (115 J)/(.325 kg)(9.8 m/s2)
h = 36 m

Answer 2

at the highest point, work done = potential energy.
Hence, 115= mgh , where m=mass,g=10ms-2,h=height of the highest point, ==> h = 115/mg = 115/(0.325x10) ~ 35.4m .