2007-01-04 07:50:42 · 26 answers · asked by Koapaka 2 in Entertainment & Music ➔ Polls & Surveys
he only likes Road Runners
plus there were no shops in the desert
2007-01-04 07:52:35 · answer #1 · answered by Anonymous · 0⤊ 0⤋
Road runner is a rare luxury commodity not sold through traditional channels, and ACME is a diversified equipment manufacturer not specializing in food products, lol.
2007-01-04 07:55:57 · answer #2 · answered by KatGuy 7 · 0⤊ 0⤋
its a tv show!!!
if wile. E. coyote bought food there would be no show. who said he bought the acme products. maybe he stole them
2007-01-04 07:54:45 · answer #3 · answered by beachbum 2 · 0⤊ 0⤋
Like a ACME frozen roadrunner tv dinner?
2007-01-04 07:52:35 · answer #4 · answered by Rowan 7 · 1⤊ 0⤋
The same reason You ask questions like this. it's pointless yet you still feel the need to do it.
Sorry, I'm trying, but I can not put myself in the shoes of you or Willi E. --- so can't help with an answer.
2007-01-04 07:58:46 · answer #5 · answered by nor2006 3 · 0⤊ 0⤋
He didn't have money! He had an ACME credit card and they don't sell food. The reson we haven't seen anything new from him is he's in jail for credit card fraud.
2007-01-04 07:55:16 · answer #6 · answered by Summer Sunset McGee 3 · 0⤊ 0⤋
would you have watched that cartoon if it consisted of the coyote sitting down to dinner and eating? where's the intrigue in that?
btw... i just bought the roadrunner cartoon dvd set... the director's cut. you'd never believe the things that bird said that they had to censor with "meep meep!"
2007-01-04 07:57:50 · answer #7 · answered by Anonymous · 0⤊ 0⤋
The thrill was in the chase - and he was a coyote dude - he wasn't smart enough to realize that!
2007-01-04 07:52:51 · answer #8 · answered by JustMe 2 · 1⤊ 0⤋
He must have otherwise he would have starved to death by now! Perhaps he just liked the taste of wild game.
2007-01-04 07:52:23 · answer #9 · answered by Lulamilu 3 · 0⤊ 0⤋
Its the thrill of the hunt
2007-01-04 08:12:33 · answer #10 · answered by joe n christina S 2 · 0⤊ 0⤋