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help me with this question

what is the square root of negative 6

2007-01-04 07:42:40 · 7 answers · asked by ntisme 5 in Science & Mathematics Mathematics

7 answers

i*sqrt(6) for complex numbers (no solution for real numbers)

2007-01-04 07:46:21 · answer #1 · answered by supersonic332003 7 · 0 0

Hi nick-

To take the square root of a negative number, mathematicians designated 'i' to be √-1. Numbers including an 'i' are called "imaginary". Using this, we can use the rule that √a ·√b = √ab to find √-6.

We can say that √-6 is equal to √-1 · √6, and so √-6= i√6. A general rule for finding √-a is that it is equal to i√a.

Hope this helped!

2007-01-04 15:47:22 · answer #2 · answered by Texas Cowgirl 3 · 2 0

the answer is i times square root of 6. it's a complex number because i stands for the square root of negative numbers.

2007-01-04 15:50:09 · answer #3 · answered by sWtnsiMpLe 3 · 0 0

it's an imaginary number. You can't have a rational square root of a negative, since if you multiply two negs you get a positive, and two positives also yields a positive, and to be a root, they need to be equal. If you had an imaginary "half negative" or something like that, you might be able to have one.

2007-01-04 15:46:31 · answer #4 · answered by loon_mallet_wielder 5 · 0 0

By definition, i^2 = -1 => i = +/- sqrt -1 (keep positive value only)
=> i = sqrt -1

then sqrt -6 = sqrt (-1 x 6) = sqrt -1 x sqrt 6 = i x sqrt 6 =i x 2.45

Answer : 2.45i


An other example: sqrt -64 ?

sqrt -64 = sqrt (64 x -1) = sqrt 64 x sqrt -1 = 8 X i = 8i


In general : sqrt -a = sqrt(a x -1) =sqrt a x sqrt -1 = sqrt a x i

= i sqrt a

2007-01-04 16:33:50 · answer #5 · answered by frank 7 · 0 0

in real number, it is not possible to square root a negative number. However, you can do in in complex number.

sqr(-16)= 4i and -4i

2007-01-04 15:47:18 · answer #6 · answered by      7 · 0 0

The answer is an imaginary number
i(6)
the squareroot is in parentheses

2007-01-04 15:47:45 · answer #7 · answered by Anonymous · 0 0

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