2007-01-04 04:11:12 · 6 answers · asked by Jack 2 in Science & Mathematics ➔ Mathematics
Hi, and thank you very much for the answers. But is there another way other than using a different base?
2007-01-04 08:36:28 · update #1
In base three!
In base ten (the usual base) 213 dollars is 2 hundreds one ten and 3 ones so 213 = 2*100 +1*10+ 3*1. In base ten 11 is 1*10+1*1 which is just eleven. But in base three, 11 is 1*3+1*1 which is 4. In binary (computer bits 0s and 1s) 11 is 1*2+1*1. So it is just a different base system, nothing to do with clock arithemtic (which exists but is something totally different).
2007-01-04 04:14:17 · answer #1 · answered by a_math_guy 5 · 3⤊ 1⤋
2+2 = 11 in base 3 i.e. imagine a clock where you only have the numbers 0, 1 and 2. Adding 2+2 = 4 which is 1 on the digits clock and one complete revolution i.e. 3*1 + 1 = 4.
2007-01-04 04:15:04 · answer #2 · answered by Chris C 2 · 2⤊ 0⤋
Indeed in base 3 . Isuspect the clock they refer to is as below
0
2 1
It is a 3 point clock as its base 3
If you start at 2 and move 2 numbers round clockwise you reach 1
This clock arithmetic gives the answer to the question what is x modulous y.
In this case we are in base 3. Say we want to find out what is 7 mod 3.Then start at zero and count round clockwise 7 you will end up on 1 so 7 mod 3 =1
There is a lot more to it than this as I'm sure you'll find out soon :-)
2007-01-04 04:19:28 · answer #3 · answered by Selphie 3 · 1⤊ 0⤋
Uh, yeah. Ya'll lost me there. Reading your question and the answers made me realize I am not as smart as I thought I was!
2007-01-04 04:20:21 · answer #4 · answered by Semi-charmed 4 · 0⤊ 2⤋
i dont know that doesn't make sense
2007-01-04 04:13:47 · answer #5 · answered by Patrick E 3 · 1⤊ 0⤋
Que?! O_o ?
2007-01-04 04:16:30 · answer #6 · answered by Can YOU make me LOL? 2 · 0⤊ 3⤋