A hosepipe with area 0.05m^2, ejects water at 5m/s. If the density of water is 1000kg/m^3.
2007-01-04 03:32:40 · 4 answers · asked by jeanpace89 1 in Education & Reference ➔ Homework Help
mass of water flowing per second is volume of water per second times density of water.
volume of water per second is velocity * area.
area = 0.05m^2
velocity = 5m/s
volume = 0.05m^2 * 5m/s = (0.05*5)m^3/s
density = 1000kg/m^3
mass/s = (0.05*5*1000)kg/m^3*m^3/s
= 250 kg/s
mass in 1 second is 250kg
2007-01-04 05:14:17 · answer #1 · answered by George C 3 · 0⤊ 0⤋
Vol of water=area x length=0.05 x 5 =0.25m^3
Mass=density x volume =1000 x 0.25 = 250kg.
2007-01-04 19:23:00 · answer #2 · answered by Anonymous · 0⤊ 0⤋
Determine the flow volume... is equal to .05*5. you get an answer in m^3 so compare to density.
2007-01-04 13:37:25 · answer #3 · answered by bfleung18 2 · 0⤊ 0⤋
volume per second = cross sectional area * flow rate
volume per second = 0.05 * 5 = 0.25 m^3/s
mass per second = volume per second * density
mass per second = 0.25 * 1000 = 250 kg per second
2007-01-04 11:39:53 · answer #4 · answered by Mike 5 · 0⤊ 0⤋