please help!!!
i dont know how to work with the tan4x
2007-01-04 02:44:51 · 5 answers · asked by rachel123go 3 in Science & Mathematics ➔ Mathematics
Let's get you started. Let u = 2x
and solve tan 2u -tan u = 0 in the range -8*pi < u < 0.
Good luck
2007-01-04 02:57:43 · answer #1 · answered by steiner1745 7 · 0⤊ 0⤋
tan4x=tan2x
4x=n(pi)+2x nis integer
2x=n(pi)
x=npi/2
according to given domain values of n may be found
2007-01-04 10:58:31 · answer #2 · answered by tarundeep300 3 · 0⤊ 0⤋
(sin 4x/cos4x)-(sin2x/cos2x)=0
(sin4x*c0s2x)-(cos4x*sin2x)/cos4x cos2x=0
sin(4x-2x)/cos4x cos2x=0
sin(2x)=0
2x=n*pi
from ur condition
-4pi
-8
since x=n*pi/2
so possible values of x are -7pi/2,-6pi/2,-5pi/2........-1pi/2
2007-01-04 10:59:27 · answer #3 · answered by miinii 3 · 0⤊ 0⤋
substitue 2x = a
Then you have:
tan(2a) - tan(a) = 0
Then use : tan(2A) = 2 tan A / (1 â tan²A)
2007-01-04 11:01:53 · answer #4 · answered by dantuck_7 1 · 0⤊ 0⤋
wat good boo
2007-01-04 10:52:19 · answer #5 · answered by swig 1 · 0⤊ 1⤋