2\/27 + 4\/2 \/= square root
2007-01-04 02:29:27 · 6 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
2v27+4v2=
2v9*3+4v2=
6v3+4v2-----------Answer
2007-01-04 02:33:05 · answer #1 · answered by Dave aka Spider Monkey 7 · 1⤊ 0⤋
"2\/27 + 4\/2"
2V9*3 + 4V2
2*3V3 + 4V2
6V3+4V2
That's as much as I can simplify with perfect square roots.
Answer: "6V3 * 4V2"
2007-01-04 02:39:47 · answer #2 · answered by ViCKi!™|` 5 · 0⤊ 0⤋
2\/27 + 4\/2 \/= square root
=2V(9*3) +4V2
=2V9V3 =4V2
=6V3+4V2
Tht's as far as you can simplify.
2007-01-04 02:50:49 · answer #3 · answered by ironduke8159 7 · 0⤊ 0⤋
2 (sq rt 27) = 2[sq rt (9 x 3)] = 2 x 3 (sq rt 3) = 6 (sq rt 3)
4 (sq rt 2) cannot be further simplified.
Their sum is:
6 (sq rt 3) + 4 (sq rt 2).
We can factor out a two from each term to get the following:
2(3 sq rt 3 + 2 sq rt 2).
2007-01-04 03:01:37 · answer #4 · answered by MathBioMajor 7 · 0⤊ 0⤋
27=9*3
V9=3
2*3V3+4V2=6V3+4V2
2007-01-04 02:33:36 · answer #5 · answered by Shanna J 4 · 0⤊ 0⤋
27+4V
2007-01-04 02:32:11 · answer #6 · answered by guRl 6 · 0⤊ 0⤋