Arithmetic confusion ......how to solve it ....Where did 1dollar go?

Question

3 friends collected 30d by 10d each and from a shop they purchased something in 30d for their common use.
After they went out of the shop, shopkeeper thought oh! price was 25d he charged 5d extra, so ha gave 5d to his servent to run behind them and return back, as they are not went so far away yet.

Servent stole 2d and returned the friends 3d only.
Now three of them took back 1d each,
So every one spent 9d.
(9x3=27), 27d+2d (stolen by servent)= 29d

Where did 1d go?, as total was 30d.
please solve the confusion of one missing d.

Answer 1

Answer is $27- $2 = $25 final price

The man stole $2 from the combined sum of the 3 x 9

The missing dollar is a fictitious amount.

Answer 2

This is a very old problem. The clue is to keep track of your signs: the 27d represents money going into the shop. The 2d is money going out of the shop. These two amounts should not be added because they are opposite in nature; the 2d should be subtracted leaving 25d as the amount received by the shop.

Note also that if you change the figures, this doesn't work: suppose the price was only 20d and the servant stole 7d, returning 3d to the friends. They'd have still spent 27d between them, but if you add the 7d you get 34d which is clearly not a meaningful figure.

Answer 3

123's answer is real, yet I doubt it's going to make lots experience to you. An arithmetic progression (it incredibly is the classic term) is a set wherein each and every term is comparable to the previous one plus (or minus) a persevering with distinction. If a is the 1st term and d is that consistent distinction, the 2d term would be a+d, the third term would be a+d+d = a+2d, the fourth term would be a+2d+d = a+3-d, etc. frequently, for this reason, the n-th term is a+(n-a million)d. on your case, you're advised that a=6 and that a+11d=28. Subtracting, you get 11d=22 and d=2. So the 18th term is a+17d = 6 + 17*2 = 40. For the 2d question, a=4 and a+d=8, so d=4 and a+15d = 4 + 14*4 = 60. do exactly no longer overlook that the n-th term is a+(n-a million)d -- in different words, do no longer overlook to subtract a million!

Answer 4

Each of the three friends didn't "spend" $9. They "spent" $8-1/3 on $25 worth of goods - $25/3. They have $1 in their pocket and $2 was stolen from them.

($8-1/3 X 3) + ($1 X 3) + ($2) = $25 + $3 + $2 = $30

There is no missing dollar.

Answer 5

I can't articulate it BUT: Count the fingers on your hand. 1, 2, 3, 4, 5, 6, 7, 8, 9, 10. Now count back down on one hand: 10, 9, 8, 7, 6.... and you still have 5 left. 6 + 5 = 11. 'Think your question is related.

Answer 6

This is a old riddle that involves order of operations.
The remaining 5 dollars is to be divied by 3 -----> 5/3 = 1.6666
Each patron keeps a dollar and gives the bellboy .66666

[ .66666 x 3 = 1.999999 ]

Answer 7

This question needs to be retired.

Answer 8

add never multiply and there is no missing dollar