construct a pedigree to show how a sex-linked disorder may be inherited by daughter.
2007-01-04 01:16:25 · 3 answers · asked by nargis 2 in Science & Mathematics ➔ Biology
Sex linked disorders are carried (mostly anyway) on the X chromosome. Females humans have 2 X chromosomes in theire karyotype. XX =female XY = male.
Say a carrier female mates with an afflicted male.
(Little x represents a chromosome with the affliction... but actually is usually indicated with a line drawn through the upper right arm of the X. I cant show it using this format.)
Carrier female = Xx
Afflicted male = xY
Xx + xY (possible offspring are listed below.
Xx XY xx and xY (the last two are afflicted and the first one Xx is a carrier, xx is the afficted daughter)
Hemophilia and color blindness follow these kinds of inheritance.
2007-01-04 01:35:59 · answer #1 · answered by docrider28 4 · 1⤊ 0⤋
A pedigree chart is a circle for a femal and a square for a female with horizontal lines between mated pairs and a vertical line down to a grouping of progeny.
See an example by following the link below.
2007-01-04 02:02:36 · answer #2 · answered by Shanna J 4 · 0⤊ 0⤋
Provides a couple with the probability of their children being completely healthy. If there is a significant chance that the baby will be born with a deadly or life-ruining disease, this may affect their decision in having a child.
2016-05-23 02:24:47 · answer #3 · answered by Anonymous · 0⤊ 0⤋