2007-01-04 00:43:23 · 11 answers · asked by tameka w 1 in Science & Mathematics ➔ Mathematics
1/3 (4/12 reduced)
2007-01-04 00:45:29 · answer #1 · answered by David B 6 · 0⤊ 0⤋
enable’s call the Quarters "A", the Dimes "B", the Nickels "C", and the Pennies "D", merely to simplify issues slightly. the answer will artwork inspite of which coin is which letter, so we are going to easily commence the first row with ABCD. A B C D Now for the 2d row, if the 4 rows must be aligned as a 4x4 grid, our 2d coin B can't be in any of the first 3 slots because it would want to contact the first coin B diagonally or vertically. So B must be contained in the merely good slot. further, coin C must be contained in the first slot. Then A can't be contained in the 2d slot, so it is going contained in the third, and D is going contained in the 2d. that can provide us: A B C D C D A B For the third and fourth rows, we are able to easily reproduction the first and 2d rows. Does that violate a given rule? No, it would not! The puzzle really particular that each row had to have one in each of each coin; it did not say that each column had to have one in each of each besides. and considering same money interior a similar column are separated by 1 diverse coin, the guideline about money touching is likewise suggested. A B C D C D A B A B C D C D A B As my challenge line suggested, there are a approach of techniques to do it. listed right here are merely a number of the different techniques: Staggered: the priority requested "how do you line up...", yet did not specify that the end result had to be in a 4x4 grid. So enable's line up the 4 rows interior a 4x7 grid: A B C D x x x x D A B C x x (x = empty area) x x C D A B x x x x B C D A Non-horizontal rows: this may artwork if "rows" are allowed to point in any route. celebration with one horizontal, one vertical, and a couple of diagonal rows: A C D A B D A x B x x x x C B x x C x x B x D x x x D A x x C Spacing, the merely good frontier: the priority would not specify that the 4 rows might want to be in the present day adjoining. for this reason, you may want to easily bypass ABCD in each row and go away area between them: A B C D A B C D A B C D A B C D adjoining: the priority would not even specify that the rows ought to finally end up above or lower than one yet another. for this reason you may want to position the 4 human being rows themselves into one row: A B C D A B C D A B C D A B C D The trick is that you may't examine obstacles into the priority that are not there. If the priority would not specify that the answer must be a particular way, you may imagine "outdoors the field" and answer it a diverse way!
2016-12-01 19:41:56 · answer #2 · answered by rothberg 4 · 0⤊ 0⤋
There are 12 coins (6+4+2=12), 4 of which are dimes. That means the probability of dimes is 4/12, or 1/3.
2007-01-04 00:51:21 · answer #3 · answered by Kilroy 4 · 0⤊ 0⤋
1 in 3
2007-01-04 00:46:43 · answer #4 · answered by the atomic penguin 2 · 0⤊ 0⤋
12 to 1
2007-01-04 00:47:24 · answer #5 · answered by steak 3 · 0⤊ 1⤋
its 4/12. draw a tree diagram. there is a 6/12 chance to get nickles, 4/12 dimes and 2/12 quarters - because there are 12 coins in total and 2 quarters.
2007-01-04 00:46:57 · answer #6 · answered by deearulz 2 · 0⤊ 0⤋
4/12
2015-03-19 13:48:31 · answer #7 · answered by Barbara Hopkins 1 · 0⤊ 0⤋
1 in every 3 draws.
Your coin total is 12. 4 draws from 12 is the answer.
2007-01-04 00:54:00 · answer #8 · answered by bleuzmask 2 · 0⤊ 0⤋
1/2
12 coins in total and 6 of them which is half the amount are nickles so chances are 50% of the time it will be a nickle.
2007-01-04 00:45:19 · answer #9 · answered by Anonymous · 0⤊ 2⤋
Four out of twelve chances ... or one in 3 .... or 33.3333 %
... a probability ratio of 0.33333
2007-01-04 00:50:24 · answer #10 · answered by Lochdan 2 · 0⤊ 0⤋