i am a girl teenager living in milan, italy and i want to start modeling. i dont know how and where. i dont want to pay outragious amounts of money to start. plaese tell me if you have any conections.
2007-01-04 00:40:07 · 6 answers · asked by no1 1 in Beauty & Style ➔ Fashion & Accessories
A reputable agency will not ask you for a dime! You need to call agencies and go to interviews. If they like you they will pay for the pictures.
Good Luck!
2007-01-04 00:41:59 · answer #1 · answered by Lauretta R 3 · 0⤊ 0⤋
From what I've heard the reputable agencies don't charge models anything. If an agency tries to get you to pay, walk out. If you're in Milan, Italy there must be dozens (at least) of reputable modeling agencies you could go to. Try as many as you can. Just realize that it's a terribly competitive business and you may be a gorgeous girl but just not what the agencies are looking for at the moment. Good luck! Ciao.
2007-01-04 08:53:35 · answer #2 · answered by Anonymous · 0⤊ 0⤋
Have your parents do this with you.
I am an International Talent Scout looking for new talent. I work for an invitation only company, so send me an email if you would like more information, include why you want to be a model and what you hope to gain by it. If you can inc a pic of you, (NOT NUDE) and an email I can reach you at, do NOT include any personal information, just the email. This is not a guaranteed job offer this is an opportunity. This is legit. Visit my webpage
http://www.squidoo.com/internationaltalentscout/ for my email and a few more details.
2007-01-04 11:28:06 · answer #3 · answered by sweetitalianyank5000 1 · 0⤊ 0⤋
Send you pictures to Ford and Elite models. Count yourself lucky if they're interested. DON'T send any money ANYWHERE.
2007-01-04 08:42:28 · answer #4 · answered by BarbieQ 6 · 0⤊ 0⤋
send pictures to abercrombie & Fitch
2007-01-04 09:14:34 · answer #5 · answered by roxy101 2 · 1⤊ 0⤋
keep looking online. or u could audition for a reality show. good exposure.
2007-01-04 08:46:30 · answer #6 · answered by miseducated 2 · 0⤊ 0⤋