16 + 24h + 9h² / 6h + 8
(4 + 3h)(4 + 3h) / 2 (3h + 4)
4 + 3h / 2
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2007-01-04 02:13:01
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answer #1
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answered by SAMUEL D 7
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16+24h+9h² divided by 6h+8 = 3h+4 over 2
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2007-01-04 10:08:40
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answer #2
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answered by aeiou 7
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OK, I'll write h^2 for h squared - this is the usual notation in text.
(16 + 24h + 9h^2) / (6h + 8): factorise both parts. Write 16 + 24h + 9h^2 as 9h^2 + 24h + 16 if it helps you.
Now, 9h^2 + 24h + 16 = (3h + 4)^2 and 6h + 8 = 2(3h + 4)
so (16 + 24h + 9h^2) / (6h + 8)
= (3h + 4)^2 / [2(3h + 4)] and a common factor of 3h+4 cancels out
= (3h + 4) / 2
= (3/2) h + 2, for h not equal to -4/3 (since then the original expression gives 0/0 which is undefined.)
2007-01-04 08:19:52
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answer #3
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answered by Scarlet Manuka 7
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Let's rearrange the equation...
[9h^2+24h+16] / 6h+8
First u can factorise 9h^2+24h+16 to (3h+4)(3h+4)
-example of (a+b)(a+b)=a^2+2ab+b^2-
Thus, u will arrive to this equation,
[(3h+4)(3h+4)] / 6h+8
Now, there's a common factor of 2 in 6h+8..so factorise it to get
2(3h+4).
And therefore , ur equation should be [(3h+4)(3h+4)] / 2(3h+4)..
Now,u can solve the equation... Note: You can't depend on ppl for answers! Solve the last step by yourself! And ur answer should be (3h+4)/2
2007-01-04 11:35:12
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answer #4
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answered by r4d3z 2
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hi...
the answer can be like this...
16+24h+9h^2
reframing the eqn
9h^2+24h+16
so the factors will be: (3h+4)(3h+4)
(3h+4) (3h+4)/(6h+8) which will be
(3h+4)(3h+4)
....................... one term from numrtr and denomrtr cancels
2(3h+4)
the answer is (3h+4)/2
2007-01-04 08:41:38
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answer #5
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answered by devi 2
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