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(1) It spirals back toward Earth (2) It achieves a geosynchronous orbit (3) It spirals outward away from the earth (4) Any of the above are possible.

What is escape velocity? I don't understand the question.

2007-01-03 21:52:06 · 4 answers · asked by Kala J 3 in Science & Mathematics Physics

4 answers

http://en.wikipedia.org/wiki/Escape_velocity
explains the question and gives you the answer too.

2007-01-03 22:04:51 · answer #1 · answered by Anonymous · 0 0

When in orbit, you have escaped the earth's gravitational force through your escape velocity to be in an orbit in the first place. As you revolve around the chosen body. its gravitational pull makes you orbit. The case with moon vis a vis the earth and so on.
So I guess you need to rephrase your question.
However the escape velocity needed to neutralise the earth's gravitational pull is roughly 80KM / Sec

2007-01-04 05:29:31 · answer #2 · answered by vaddadi 2 · 0 0

destroy out speed is the speed you want to go away the planet so as that with none extra push you keep transferring away always. Orbital speed is the speed mandatory to circle the planet on a similar altitude with no need farther or nearer. From any round orbit you want to boost up by a area of the sq. root of two to get to flee speed. For Low Earth orbit, orbital speed is 17,500 MPH, and destroy out speed is the sq. root of two (about a million.414) cases as quick, or quite lower than 25,000 MPH. The Apollo missions entered Earth orbit at 17,500 MPH and then restarted the third degree engine to improve speed to easily about 25,000 MPH and bypass to the Moon.

2016-12-01 19:37:17 · answer #3 · answered by ? 4 · 0 0

It escapes.

A normal planetary body is also modeled as a gravity well.

At certain "energy states", a satellite can escape the infinite circling of the well.

2007-01-03 22:13:04 · answer #4 · answered by _LEV_ 2 · 0 0

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