Charges gets concentrated only at edges and tip (sharp points)....why?

Question

"This is due to the reason that suface charge density is inversly proportional to Area ,therfore smaller is the area more charge density seems to be at the edges "

this is the answer everybody is giving....

but at the tips the charges tends to repel due to repulsive force...then how come charges to concentrate at the sharp edges and tips

come on dudes give me the nice answer along with ur email id

Answer 1

I reckon you already know every system strives for to be in the lowest state of energy and how charges behave in a conductor, namely excess charges lie only on the surface of a conductor in order to get away from each othe away as far as possible. From those two concepts I assume that you already know, now consider the following two scenarios:

1. There are excess charges in a perfect round sphere conductor. Charges on this sphere of course would want to spread out on the surface as far away from each other as possible. The end result is a perfectly evenly distributed charges on the sphere. If a single charge happens to get closer to any one particular charge, this single charge will experience a repelling force to move it into its 'properly' distributed location. In this way, the system is dynamically self correcting itself continuously. Once you understand this concept, consider scenario 2.

2. There is a line conductor, say 4 centimeters long, with excess charge on it. The initial distribution of charges can be anyway. For the clarify of arugment, let us assume the charges( 6 of them) lie evenly on every 1 centimeter mark: 0 cm, 1cm, 2cm,3cm, 4cm. From the perspective of the charge on 2cm mark, in the middle, it experiences perfect symmetry on either side. However, the charge on either end is another story. Take the charge on 1 cm mark for instance, there is one charge on the left side and thus facing force from one left charge while it experience forces from 3 repelling charges on the right. The end result is a net force forcing this charge to move closer to mark 0. As you can see, the overall picture is that charges will be forced to move closer to mark 0 and mark 4.

You can extend this argument to a 6 cm, or any length, line conductor and see how charges on 1cm and 2 cm marks will be pushed to left and charges on 5cm and 6 cm mark will be pushed to right. Thus making charges accumulate on sharp point or edges.

This picture can be extended to, say a contusion sticking out of a sphere conductor.

This is the reason why charges ostensibly accumulate on the edge or sharp point.

Your reasoning that charges at the tips tend to repel due to repulsive force is correct, but it doesn't take the overall picture of what repulsive forces those charge face, namely that all the charges that are being pushed away from the side opposing the tip. Of course there are repulsive forces among charges at the tip, but the repulsive forces attributed from the non-tipped side are greater. The charges thus are been forced to accumulate on the tip where there exists an equilibrium between the repulsive forces within the charges at the tip and the forces from the 'opposing side.'

Answer 2

My guess is, is that the edges have exposed electrons which of course would require less energy to disrupt the electons in the element. Although electrons repell, the tighter the ionic bond in the material means the harder they are to disrupt.

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Answer 3

The tips and edges are the furtherest that those charge can get from the rest of the charges that reside on the item.

Answer 4

This is a very 'sharp' question. Thanks to the repel the concentration of charge is a mystery for me. Please send me the answer when you know.
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Th