Find the roots of the quadratic equation
2007-01-03 18:11:08 · 7 answers · asked by Lost in math 1 in Science & Mathematics ➔ Mathematics
(z+6)(z-3)=0
z=-6 or 3
2007-01-04 11:42:26 · answer #1 · answered by Anonymous · 4⤊ 0⤋
Factor:
z^2+3z-18=0
(z-3)(z+6)=0
Therefore the roots are z=3 and z= -6.
2007-01-03 18:14:52 · answer #2 · answered by GeorgeMKLam 1 · 2⤊ 0⤋
z² + 3z - 18 = 0
(z + 6) (z - 3) = 0
z + 6 = 0 or z - 3 = 0
Thus, z = -6 or z = 3
2007-01-03 18:25:27 · answer #3 · answered by starryyellow 1 · 2⤊ 0⤋
Z squared + 3z+18=0...
therefore, factorise: (z-3)(z+6)=0
therefore: either z-3=0 or z+6=o..
so.... z-3=0
~ z=3
or
z+6=0
~ z= -6...
the answer is z=3 or z=-6....
2007-01-03 18:22:31 · answer #4 · answered by Losh 5 · 2⤊ 0⤋
Use the quadratic formula or factor it. z^2+3z-18 = (z+6)*(z-3)
2007-01-03 18:14:30 · answer #5 · answered by gp4rts 7 · 2⤊ 0⤋
z^2 + 3z - 18 = 0
z^2 + 6z - 3z - 18 = 0
(z^2 + 6z) - (3z + 18) = 0
z(z + 6) - 3(z + 6) = 0
(z - 3)(z + 6) = 0
z = 3 or z = -6
Th
2007-01-03 18:22:01 · answer #6 · answered by Thermo 6 · 2⤊ 0⤋
guys...please don't answer kids' homework questions just to get yourself points.... sheesh.
2007-01-03 18:20:06 · answer #7 · answered by abatardi 3 · 0⤊ 2⤋